3.1). The following plot represents the potentiometric curve of acid with NaOH. Volume of NaOHL m a) Determine the volume of NaOH at half equivalence point? b) Calculate k value of the acid. a 3.1). The following plot represents the potentiometric curve of acid with NaOH. рн pH-pka 11mL Volume of NaOH/mL a) Determine the volume of NaOH at half equivalence point? 11ml b) Calculate k, value of the acid. 6.309x10 3.981x105
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- 0-25 Nor 1lit of Hcl mixed Ceith OINO somlor Hel, then find Normalibs q folition is A) 0. 16 B) 0.24 C) 0. 32 )) 0.48Calc. the alkaline strength of a sample of impure K2CO3 in terms of percent K2O from the ff. data: wt. of sample = 1.000g; HCL used = 55.90 ml;NaOH used = 0.42ml; 1.000mlNaOH 0.008473 g KHC2O4 .H2C2O4 . 2H2O; 1.000ml HCL 2.500 ml NaOH.3. Complete neutralization of 10 ml of phosphoric acid solution by NaOH 0.I N in the presence of phenol phthalein until the appearance of purple color (pH, = 9) 11 ml. of NaOH is consumed. (a) What is the concentration of phosphoric acid? (b) Calculate the indicator error. pk2.1 pK. - 7.2 pK - 124
- 1. Amino acids are the building blocks of proteins. The simplest amino acid is glycine, NH2CH2CO2H. There are three forms in equilibrium with one another. +NH3CH2CO2H(aq) + H2O(l)↔+NH3CH2CO2-(aq) + H3O+(aq) Ka = 4.5 x 10-3 +NH3CH2CO2-(aq) + H2O(l)↔ NH2CH2CO2-(aq) + H3O+(aq) Ka = 1.7 x 10-10 If the pH of a natural system (i.e. your body) is 7.2, in what form is the amino acid found? Justify your answer both with rational as well as a quantitative rationale. 2. Sulfanilic acid, which is used in making dyes, is made by reacting aniline with sulfuric acid: H2SO4(aq) + C6H5NH2(aq)→ + H2O(l) a) If you want to prepare 150.0 g of sulfanilic acid, and you expect only an 85% yield, how many milliliters of aniline should you take as a starting material? (ρaniline = 1.02 g/ml) b) Give the approximate values for the following bond angles in sulfanilic acid: A ______B ______ C ______D _______ c)Give the appropriate hybridization for the following atoms in sulfanilic acid:A ______B ______ C ______D…A solution is prepared in which [Pb2+]= 0.0150 M and [Br 0.00350 M. Given that PbBr2 has a Kgo = 2.1 x 106, which of the following is true? %3D Select one: O a. Qsp Kg. and the solution is supersaturated %3D O d. Q.,< Kgp and the solution is supersaturatedBased on the following data for the fırst order reaction J products, calculate the rate constant k (in s1). Time [J] Os 1.0000 M 900 .5231 3000 .1153 O 2.9 x 104 O 1.4 x 103 O 5.3 x 10-4 О 1.0 х 10-3 O 7.2 x 10-4
- The expression for K and K, for the reaction PH,BCI,(s) - PH,(g) + BCI,(g) K = [PH,J[BCI,1/[PH3BCI3] and K, = P(PH,)'p(BCI,) Select one: True FalseThe following is an alpha plot for a monoprotic weak acid, HA. 1.0 CL 0.5 2 4 6 pH 8 10 12 14 HA A ►Ans. 17.15 mg. 54) A 1.000-g sample of a mixture which contains only NaCl and KCl gare a precipitate of AgCl which weighed 2.000 g. What are the percentages of Na and K in the mixture? ins 10 g Ans. 44.77% K; 5.75% Na. 1:J 55. I- can be sernarated from othor
- What is the gram solubility (in g/L) of Ag,So, in water, given its Ksp 1.40 x 105 and its Molar Mass is 311.80 g/mol. Leave answer in 3 significant figures (e.g. 30.2).Benzoic acid, C6H5COOH (pKa = 4.19), is only slightly soluble in water, but its sodium salt, C6H5COO Na", is quite soluble in water. In which of the following solutions will benzoic acid dissolve more readily than in pure water? O NAHCO; O LIOH O H;SO4 O HCI OK½CO33) What is the pH of a 0.02 M solution of sodium propionate? (12 pts) Reaction of sodium propionate in water: Pr (aq) + H₂O (1) ⇒ HPr (aq) + OH-(aq) Ka= 10-4.⁹ *Hint* This is a Kb problem therefore you must convert ka to Kb. You can assume that the sodium propionate dissociates completely from the propionate and is not involved in any other important reactions. a) Is this the conjugate base or an acid that you are adding to solution? b) Write down the Mass-Balance Relations, the Proton Balance Relation and the c) Equilibrium Relation. Calculate the pH using both an analytic method, and by drawing the predominance diagram. *Hint* [OH-]=[HPr].