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To determine:The shape of
Concept Introduction:
- To predict the shapes, we have to considerer the special distribution of the atoms and the pairs of free electrons.
- The pairs of free electrons are those do not form part of bonds between atoms.
- The electron dot structure shows the valence electrons distribution around the atoms.
Number of bonds | Number of pairs of free electrons | Shapes |
2 | 0 | Linear |
2 | 3 | Linear |
2 | 1 | Bent |
4 | 0 | Tetrahedral |
4 | 2 | Square planar |
3 | 0 | Trigonal planar |
5 | 1 | Square pyramidal |
3 | 1 | Trigonal pyramidal |
6 | 0 | Octahedral |
![Check Mark](/static/check-mark.png)
Answer to Problem 8.1P
Solution:
Trigonal pyramid.
Explanation of Solution
The electron dot structure of
It has three bonds and one pair of lone electrons. So, its shape is trigonal pyramid.
(c)
To determine:The shape of
Concept Introduction:
- To predict the shapes, we have to considerer the special distribution of the atoms and the pairs of free electrons.
- The pairs of free electrons are those do not form part of bonds between atoms.
- The electron dot structure shows the valence electrons distribution around the atoms.
Number of bonds | Number of pairs of free electrons | Shapes |
2 | 0 | Linear |
2 | 3 | Linear |
2 | 1 | Bent |
4 | 0 | Tetrahedral |
4 | 2 | Square planar |
3 | 0 | Trigonal planar |
5 | 1 | Square pyramidal |
3 | 1 | Trigonal pyramidal |
6 | 0 | Octahedral |
![Check Mark](/static/check-mark.png)
Answer to Problem 8.1P
Solution:
Linear.
Explanation of Solution
The electron dot structure of
It has two bonds and three pairs of lone electrons. So, its shape is linear.
(d)
To determine:The shape of
. Concept Introduction:
- To predict the shapes, we have to considerer the special distribution of the atoms and the pairs of free electrons.
- The pairs of free electrons are those do not form part of bonds between atoms.
- The electron dot structure shows the valence electrons distribution around the atoms.
Number of bonds | Number of pairs of free electrons | Shapes |
2 | 0 | Linear |
2 | 3 | Linear |
2 | 1 | Bent |
4 | 0 | Tetrahedral |
4 | 2 | Square planar |
3 | 0 | Trigonal planar |
5 | 1 | Square pyramidal |
3 | 1 | Trigonal pyramidal |
6 | 0 | Octahedral |
![Check Mark](/static/check-mark.png)
Answer to Problem 8.1P
Solution:
Octahedral.
Explanation of Solution
The electron dot structure of
It has six bonds and no lone pair of electrons. So, its shape is octahedral.
(e)
To determine:The shape of
. Concept Introduction:
- To predict the shapes, we have to considerer the special distribution of the atoms and the pairs of free electrons.
- The pairs of free electrons are those do not form part of bonds between atoms.
- The electron dot structure shows the valence electrons distribution around the atoms.
Number of bonds | Number of pairs of free electrons | Shapes |
2 | 0 | Linear |
2 | 3 | Linear |
2 | 1 | Bent |
4 | 0 | Tetrahedral |
4 | 2 | Square planar |
3 | 0 | Trigonal planar |
5 | 1 | Square pyramidal |
3 | 1 | Trigonal pyramidal |
6 | 0 | Octahedral |
![Check Mark](/static/check-mark.png)
Answer to Problem 8.1P
Solution:
Square pyramidal.
Explanation of Solution
The electron dot structure of
It has five bonds and one pair of lone electrons. So, its shape is square pyramidal.
(f)
To determine:The shape of
Concept Introduction:
- To predict the shapes, we have to considerer the special distribution of the atoms and the pairs of free electrons.
- The pairs of free electrons are those do not form part of bonds between atoms.
- The electron dot structure shows the valence electrons distribution around the atoms.
Number of bonds | Number of pairs of free electrons | Shapes |
2 | 0 | Linear |
2 | 3 | Linear |
2 | 1 | Bent |
4 | 0 | Tetrahedral |
4 | 2 | Square planar |
3 | 0 | Trigonal planar |
5 | 1 | Square pyramidal |
3 | 1 | Trigonal pyramidal |
6 | 0 | Octahedral |
![Check Mark](/static/check-mark.png)
Answer to Problem 8.1P
Solution:
Tetrahedral.
Explanation of Solution
The electron dot structure of
It has four bonds and no lone pair of electrons. So, its shape is tetrahedral.
(g)
To determine:The shape of
. Concept Introduction:
- To predict the shapes, we have to considerer the special distribution of the atoms and the pairs of free electrons.
- The pairs of free electrons are those do not form part of bonds between atoms.
- The electron dot structure shows the valence electrons distribution around the atoms.
Number of bonds | Number of pairs of free electrons | Shapes |
2 | 0 | Linear |
2 | 3 | Linear |
2 | 1 | Bent |
4 | 0 | Tetrahedral |
4 | 2 | Square planar |
3 | 0 | Trigonal planar |
5 | 1 | Square pyramidal |
3 | 1 | Trigonal pyramidal |
6 | 0 | Octahedral |
![Check Mark](/static/check-mark.png)
Answer to Problem 8.1P
Solution: Tetrahedral.
Explanation of Solution
The electron dot structure of
It has four bonds and no lone pair of electrons. So, its shape is tetrahedral.
(h)
To determine:The shape of
Concept Introduction:
- To predict the shapes, we have to considerer the special distribution of the atoms and the pairs of free electrons.
- The pairs of free electrons are those do not form part of bonds between atoms.
- The electron dot structure shows the valence electrons distribution around the atoms.
Number of bonds | Number of pairs of free electrons | Shapes |
2 | 0 | Linear |
2 | 3 | Linear |
2 | 1 | Bent |
4 | 0 | Tetrahedral |
4 | 2 | Square planar |
3 | 0 | Trigonal planar |
5 | 1 | Square pyramidal |
3 | 1 | Trigonal pyramidal |
6 | 0 | Octahedral |
![Check Mark](/static/check-mark.png)
Answer to Problem 8.1P
Solution: Tetrahedral.
Explanation of Solution
The electron dot structure of
It has four bonds and no lone pair of electrons. So, its shape is tetrahedral.
(i)
To determine:The shape of
. .concept Introduction:
- To predict the shapes, we have to considerer the special distribution of the atoms and the pairs of free electrons.
- The pairs of free electrons are those do not form part of bonds between atoms.
- The electron dot structure shows the valence electrons distribution around the atoms.
Number of bonds | Number of pairs of free electrons | Shapes |
2 | 0 | Linear |
2 | 3 | Linear |
2 | 1 | Bent |
4 | 0 | Tetrahedral |
4 | 2 | Square planar |
3 | 0 | Trigonal planar |
5 | 1 | Square pyramidal |
3 | 1 | Trigonal pyramidal |
6 | 0 | Octahedral |
![Check Mark](/static/check-mark.png)
Answer to Problem 8.1P
Solution: Square planar.
Explanation of Solution
The electron dot structure of
It has four bonds and two pairs of lone electrons. So, its shape is square planar.
(j)
To determine:The shape of
Concept Introduction:
- To predict the shapes, we have to considerer the special distribution of the atoms and the pairs of free electrons.
- The pairs of free electrons are those do not form part of bonds between atoms.
- The electron dot structure shows the valence electrons distribution around the atoms.
Number of bonds | Number of pairs of free electrons | Shapes |
2 | 0 | Linear |
2 | 3 | Linear |
2 | 1 | Bent |
4 | 0 | Tetrahedral |
4 | 2 | Square planar |
3 | 0 | Trigonal planar |
5 | 1 | Square pyramidal |
3 | 1 | Trigonal pyramidal |
6 | 0 | Octahedral |
![Check Mark](/static/check-mark.png)
Answer to Problem 8.1P
Solution: Trigonal planar.
Explanation of Solution
The electron dot structure of
It has three bonds and no lone pair of electrons. So, its shape is trigonal planar.
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