Biology
5th Edition
ISBN: 9781260487947
Author: BROOKER
Publisher: MCG
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Chapter 21.5, Problem 1CS
Summary Introduction
To propose: A model that can determine the outcome of transposition depending on the pattern of replication.
Introduction: DNA is a type of
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Home Work:
• Suppose you perform a PCR that begins with one double-strand of the
following DNA template:
+5' -СТАССТСCGGGTTGACTGСТАССТТССССGGATGCCCAAAAТТСТСGAG-3—
::::::::::::
:::::::::::: ::::
+3'-GATGGACССССААСТGACGATGGAAGGGCCCТАССGGTTTTAAGAGCTC-5'+
A. Draw one cycle of PCR reaction below the following diagram.
B. Label the template DNA, the primers, and what is happening at each step.
(1)
température
cycle #1
a. Propose three different mutations to prevent initiation, elongation, and termination of bacterial
DNA replication, respectively. Explain how/why each mutation would prevent its respective step.
(Hint: mutations can be in genes that encode proteins or regulatory DNA sequences)
b. In the early 1900s, Avery, MacLeod, and McCarty performed an experiment in bacterial cells to
determine whether DNA, RNA, or protein functions as the 'transforming molecule' (i.e. the genetic
material). In your own words, how did their experiment (depicted in the figure below) help to
answer that question?
Matching Type
Choose the directionality of the given process. (4 points)
What is the directionality of the given process? *
4 points
3'-5'
5'-3'
Exonuclease activity
Complementary strand of the
continuous strand
Addition of nucleotides going
to the replication fork
Addition of nucleotides away
from the replication fork
Chapter 21 Solutions
Biology
Ch. 21.1 - Prob. 1CSCh. 21.1 - Prob. 1CCCh. 21.1 - Prob. 2CCCh. 21.1 - Prob. 3CCCh. 21.2 - Prob. 1CCCh. 21.2 - Prob. 2CCCh. 21.2 - Prob. 3CCCh. 21.3 - Prob. 1EQCh. 21.3 - Prob. 2EQCh. 21.3 - Prob. 3EQ
Ch. 21.4 - Prob. 1CCCh. 21.4 - Prob. 1CSCh. 21.5 - Prob. 1CSCh. 21.5 - Repetitive Sequences and Transposable Elements...Ch. 21 - Prob. 1TYCh. 21 - DNA ligase is needed in a cloning experiment a. to...Ch. 21 - Prob. 3TYCh. 21 - Why is Taq polymerase used in PCR rather than...Ch. 21 - Lets suppose you want to clone a gene that has...Ch. 21 - In the CRISPR-Cas technology for editing genes,...Ch. 21 - Prob. 7TYCh. 21 - The enzyme that helps short segments of DNA move...Ch. 21 - Prob. 9TYCh. 21 - Which of the following was not a goal of the Human...Ch. 21 - Prob. 1CQCh. 21 - Briefly describe whether or not each of the...Ch. 21 - Prob. 3CQCh. 21 - Identify and discuss three important advances that...Ch. 21 - Prob. 2COQ
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- several options can be correct Consider the following segment of DNA, which is part of a linear chromosome: LEFT 5’.…TGACTGACAGTC….3’ 3’.…ACTGACTGTCAG….5’ RIGHT During RNA transcription, this double-strand molecule is separated into two single strands from the right to the left and the RNA polymerase is also moving from the right to the left of the segment. Please select all the peptide sequence(s) that could be produced from the mRNA transcribed from this segment of DNA. (Hint: you need to use the genetic codon table to translate the determined mRNA sequence into peptide. Please be reminded that there are more than one reading frames.) Question 6 options: ...-Asp-Cys-Gln-Ser-... ...-Leu-Thr-Val-... ...-Thr-Val-Ser-... ...-Leu-Ser-Val-... ...-Met-Asp-Cys-Gln-...arrow_forwardCorrect order ib which the following enzynes would operate to fix a damaged nucleotide in a human gene. a) nuclease, DNA polymerase, RNA primase b) helicase, DNA polymerase, DNA ligase c) DNA ligase, nuclease, helicase d) nuclease, DNA polymerase, DNA ligasearrow_forwardProtein Synthesis and Mutation Practice • Complete the lines below by determining the mRNA transcript and amino acid sequence. • Compare the mutant DNA strands to the wild type strand. ⚫ Circle the mutation in the mutant DNA strands and describe the type of mutation (frameshift - insertion, frameshift - deletion, point - missense, point - silent, or point-nonsense). Not all of these will be used in this assignment! Wild type DNA template: 3' TACGCGTGCACGATGCAGTAGTACATC5' mRNA transcript sequence: Amino acid sequence: Mutation #1 DNA template: 3' TACGCGTGCACGATCCAGTAGTACATC5' mRNA transcript sequence: Amino acid sequence: Type of mutation: Mutation #2 DNA template: 3' TACGCGTGCTCGATGCAGTAGTACATC5' mRNA transcript sequence: Amino acid sequence: Type of mutation:arrow_forward
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