(a) Interpretation: The dodecane, 1-hexyne , 1-decene and 1,2-dimethylbenzene should be matched with the correct set of IR frequencies. Concept introduction: IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm -1 ) is the horizontal axis and intensity is the vertical axis. As different molecules have different bonds of varying strength so they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond. IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000 − 600 cm -1 and it is the most important region as approximately all organic compounds absorb in this region. The allowed vibrational energy levels for IR transition is as follows: E = h ν ο ( ν + 1 ) Where, E is IR energy absorbed by a molecule. h is Planck's constant. ν ο is zero point vibrational level. ν is vibrational level with integer value of 1,2,3,4......

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 21, Problem 1Q

Interpretation Introduction

(a)

Interpretation:

The dodecane, 1-hexyne, 1-decene and 1,2-dimethylbenzene should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength so they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

E is IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Name of compoundFrequencies( cm -1 )VibrationsDodecane 2924(s) 1467(m) C−H stretch C−H bend1-hexyne 3311(s) 2961(s) 2119(m) C≡C−H stretch C−H stretch C≡C stretch1-decene 3049(w) 2951(m) 1642(m) C=C-H stretch C−H stretch C=C stretch1,2-dimethylbenzene 3020(s) 2940(s) 1606(s) 1495(s) 741(s) aromatic C−H stretch C−H stretch C=C stretch C−H bend aromatic C−H bend

Interpretation Introduction

(b)

Interpretation:

The phenol, benzyl alcohol, and methoxybenzene should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength, they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

Eis IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Name of compoundFrequencies( cm -1 )Vibrationsmethoxybenzene 3060( m ) 2835( m ) 1498( s ) 1247( s ) 1040( s ) aromatic C−H stretch alkyl C−H stretch aromatic C=C stretch conjugatedC−O stretch saturated C−O stretchphenol 3370( s ) 3045( m ) 1595( s ) 1224( s ) O−H stretch aromatic C−H stretch aromatic C=C stretch conjugated C−O stretchbenzyl alcohol 3330( br,s ) 3030( m ) 2950( m ) 1454( m ) 1223( s ) O−H stretch aromatic C−H stretch alkyl C−H stretch aromatic C=C stretch C−O stretch

Interpretation Introduction

(c)

Interpretation:

The 2-phenyl propanal, 1-amino octane, phenylacetate, heptanoic acid, 2-methylpropanamide, 2-pentanone and acetophenone should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength so they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

Eis IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Laboratory Techniques in Organic Chemistry, Chapter 21, Problem 1Q

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Identify and explain the IR absorption characteristics of the unknown C6H14O in the 1400 to 4000 cm-1 range. Then identify the class of the unknown compound C6H14O. At the broad peak I believe it is either an alcohol & phenol or an amine. For the second peak i think it is an alkane.

The IR spectra of nonane (C,H20) and 1-hexanol (C,H13OH) are shown below. Assign each spectrum to the correct compound and identify the frequencies and the functional groups used to support your assignment. λ (μη) 6 7 8 9 10 11 12 1314 15 2.5 100 3 5 20 4 90 80 70 60 50 40 30 20 10 4000 3600 3200 2800 2400 2000 1800 1600 1400 1200 1000 800 600 400 Frequency (cm¬') A (µm) 2.5 100 8 9 10 11 12 13 14 15 3 4 5 7 20 90 80 70 60 50 40 30 20 10 4000 3600 3200 2800 2400 2000 1800 1600 1400 1200 1000 800 600 400 Frequency (cm¬!) (%) Transmission (%) Transmission

The mass spectrum of n-octane shows a prominent molecular ion peak (m>z 114). There is also a large peak at m>z 57,but it is not the base peak. The mass spectrum of 3,4-dimethylhexane shows a smaller molecular ion, and the peak atmass 57 is the base peak. Explain these trends in abundance of the molecular ions and the ions at mass 57, and predict theintensities of the peaks at masses 57 and 114 in the spectrum of 2,2,3,3-tetramethylbutane.

Answer 2

Question

Chapter 21, Problem 1Q

Interpretation Introduction

(a)

Interpretation:

The dodecane, 1-hexyne, 1-decene and 1,2-dimethylbenzene should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength so they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

E is IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Name of compoundFrequencies( cm -1 )VibrationsDodecane 2924(s) 1467(m) C−H stretch C−H bend1-hexyne 3311(s) 2961(s) 2119(m) C≡C−H stretch C−H stretch C≡C stretch1-decene 3049(w) 2951(m) 1642(m) C=C-H stretch C−H stretch C=C stretch1,2-dimethylbenzene 3020(s) 2940(s) 1606(s) 1495(s) 741(s) aromatic C−H stretch C−H stretch C=C stretch C−H bend aromatic C−H bend

Interpretation Introduction

(b)

Interpretation:

The phenol, benzyl alcohol, and methoxybenzene should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength, they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

Eis IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Name of compoundFrequencies( cm -1 )Vibrationsmethoxybenzene 3060( m ) 2835( m ) 1498( s ) 1247( s ) 1040( s ) aromatic C−H stretch alkyl C−H stretch aromatic C=C stretch conjugatedC−O stretch saturated C−O stretchphenol 3370( s ) 3045( m ) 1595( s ) 1224( s ) O−H stretch aromatic C−H stretch aromatic C=C stretch conjugated C−O stretchbenzyl alcohol 3330( br,s ) 3030( m ) 2950( m ) 1454( m ) 1223( s ) O−H stretch aromatic C−H stretch alkyl C−H stretch aromatic C=C stretch C−O stretch

Interpretation Introduction

(c)

Interpretation:

The 2-phenyl propanal, 1-amino octane, phenylacetate, heptanoic acid, 2-methylpropanamide, 2-pentanone and acetophenone should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength so they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

Eis IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Laboratory Techniques in Organic Chemistry, Chapter 21, Problem 1Q

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 21, Problem 1Q

Interpretation Introduction

(a)

Interpretation:

The dodecane, 1-hexyne, 1-decene and 1,2-dimethylbenzene should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength so they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

E is IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Name of compoundFrequencies( cm -1 )VibrationsDodecane 2924(s) 1467(m) C−H stretch C−H bend1-hexyne 3311(s) 2961(s) 2119(m) C≡C−H stretch C−H stretch C≡C stretch1-decene 3049(w) 2951(m) 1642(m) C=C-H stretch C−H stretch C=C stretch1,2-dimethylbenzene 3020(s) 2940(s) 1606(s) 1495(s) 741(s) aromatic C−H stretch C−H stretch C=C stretch C−H bend aromatic C−H bend

Interpretation Introduction

(b)

Interpretation:

The phenol, benzyl alcohol, and methoxybenzene should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength, they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

Eis IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Name of compoundFrequencies( cm -1 )Vibrationsmethoxybenzene 3060( m ) 2835( m ) 1498( s ) 1247( s ) 1040( s ) aromatic C−H stretch alkyl C−H stretch aromatic C=C stretch conjugatedC−O stretch saturated C−O stretchphenol 3370( s ) 3045( m ) 1595( s ) 1224( s ) O−H stretch aromatic C−H stretch aromatic C=C stretch conjugated C−O stretchbenzyl alcohol 3330( br,s ) 3030( m ) 2950( m ) 1454( m ) 1223( s ) O−H stretch aromatic C−H stretch alkyl C−H stretch aromatic C=C stretch C−O stretch

Interpretation Introduction

(c)

Interpretation:

The 2-phenyl propanal, 1-amino octane, phenylacetate, heptanoic acid, 2-methylpropanamide, 2-pentanone and acetophenone should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength so they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

Eis IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Laboratory Techniques in Organic Chemistry, Chapter 21, Problem 1Q

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 21, Problem 1Q

Interpretation Introduction

(a)

Interpretation:

The dodecane, 1-hexyne, 1-decene and 1,2-dimethylbenzene should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength so they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

E is IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Name of compoundFrequencies( cm -1 )VibrationsDodecane 2924(s) 1467(m) C−H stretch C−H bend1-hexyne 3311(s) 2961(s) 2119(m) C≡C−H stretch C−H stretch C≡C stretch1-decene 3049(w) 2951(m) 1642(m) C=C-H stretch C−H stretch C=C stretch1,2-dimethylbenzene 3020(s) 2940(s) 1606(s) 1495(s) 741(s) aromatic C−H stretch C−H stretch C=C stretch C−H bend aromatic C−H bend

Interpretation Introduction

(b)

Interpretation:

The phenol, benzyl alcohol, and methoxybenzene should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength, they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

Eis IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Name of compoundFrequencies( cm -1 )Vibrationsmethoxybenzene 3060( m ) 2835( m ) 1498( s ) 1247( s ) 1040( s ) aromatic C−H stretch alkyl C−H stretch aromatic C=C stretch conjugatedC−O stretch saturated C−O stretchphenol 3370( s ) 3045( m ) 1595( s ) 1224( s ) O−H stretch aromatic C−H stretch aromatic C=C stretch conjugated C−O stretchbenzyl alcohol 3330( br,s ) 3030( m ) 2950( m ) 1454( m ) 1223( s ) O−H stretch aromatic C−H stretch alkyl C−H stretch aromatic C=C stretch C−O stretch

Interpretation Introduction

(c)

Interpretation:

The 2-phenyl propanal, 1-amino octane, phenylacetate, heptanoic acid, 2-methylpropanamide, 2-pentanone and acetophenone should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength so they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

Eis IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Laboratory Techniques in Organic Chemistry, Chapter 21, Problem 1Q

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 21, Problem 1Q

Interpretation Introduction

(a)

Interpretation:

The dodecane, 1-hexyne, 1-decene and 1,2-dimethylbenzene should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength so they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

E is IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Name of compoundFrequencies( cm -1 )VibrationsDodecane 2924(s) 1467(m) C−H stretch C−H bend1-hexyne 3311(s) 2961(s) 2119(m) C≡C−H stretch C−H stretch C≡C stretch1-decene 3049(w) 2951(m) 1642(m) C=C-H stretch C−H stretch C=C stretch1,2-dimethylbenzene 3020(s) 2940(s) 1606(s) 1495(s) 741(s) aromatic C−H stretch C−H stretch C=C stretch C−H bend aromatic C−H bend

Interpretation Introduction

(b)

Interpretation:

The phenol, benzyl alcohol, and methoxybenzene should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength, they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

Eis IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Name of compoundFrequencies( cm -1 )Vibrationsmethoxybenzene 3060( m ) 2835( m ) 1498( s ) 1247( s ) 1040( s ) aromatic C−H stretch alkyl C−H stretch aromatic C=C stretch conjugatedC−O stretch saturated C−O stretchphenol 3370( s ) 3045( m ) 1595( s ) 1224( s ) O−H stretch aromatic C−H stretch aromatic C=C stretch conjugated C−O stretchbenzyl alcohol 3330( br,s ) 3030( m ) 2950( m ) 1454( m ) 1223( s ) O−H stretch aromatic C−H stretch alkyl C−H stretch aromatic C=C stretch C−O stretch

Interpretation Introduction

(c)

Interpretation:

The 2-phenyl propanal, 1-amino octane, phenylacetate, heptanoic acid, 2-methylpropanamide, 2-pentanone and acetophenone should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength so they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

Eis IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Laboratory Techniques in Organic Chemistry, Chapter 21, Problem 1Q

Answer 6

Chapter 21, Problem 1Q

Interpretation Introduction

(a)

Interpretation:

The dodecane, 1-hexyne, 1-decene and 1,2-dimethylbenzene should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength so they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

E is IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Name of compoundFrequencies( cm -1 )VibrationsDodecane 2924(s) 1467(m) C−H stretch C−H bend1-hexyne 3311(s) 2961(s) 2119(m) C≡C−H stretch C−H stretch C≡C stretch1-decene 3049(w) 2951(m) 1642(m) C=C-H stretch C−H stretch C=C stretch1,2-dimethylbenzene 3020(s) 2940(s) 1606(s) 1495(s) 741(s) aromatic C−H stretch C−H stretch C=C stretch C−H bend aromatic C−H bend

Answer 7

Chapter 21, Problem 1Q

Interpretation Introduction

(a)

Interpretation:

The dodecane, 1-hexyne, 1-decene and 1,2-dimethylbenzene should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength so they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

E is IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Answer 8

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Name of compoundFrequencies( cm -1 )VibrationsDodecane 2924(s) 1467(m) C−H stretch C−H bend1-hexyne 3311(s) 2961(s) 2119(m) C≡C−H stretch C−H stretch C≡C stretch1-decene 3049(w) 2951(m) 1642(m) C=C-H stretch C−H stretch C=C stretch1,2-dimethylbenzene 3020(s) 2940(s) 1606(s) 1495(s) 741(s) aromatic C−H stretch C−H stretch C=C stretch C−H bend aromatic C−H bend

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Interpretation Introduction

(b)

Interpretation:

The phenol, benzyl alcohol, and methoxybenzene should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength, they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

Eis IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Name of compoundFrequencies( cm -1 )Vibrationsmethoxybenzene 3060( m ) 2835( m ) 1498( s ) 1247( s ) 1040( s ) aromatic C−H stretch alkyl C−H stretch aromatic C=C stretch conjugatedC−O stretch saturated C−O stretchphenol 3370( s ) 3045( m ) 1595( s ) 1224( s ) O−H stretch aromatic C−H stretch aromatic C=C stretch conjugated C−O stretchbenzyl alcohol 3330( br,s ) 3030( m ) 2950( m ) 1454( m ) 1223( s ) O−H stretch aromatic C−H stretch alkyl C−H stretch aromatic C=C stretch C−O stretch

Answer 13

Interpretation Introduction

(b)

Interpretation:

The phenol, benzyl alcohol, and methoxybenzene should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength, they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

Eis IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Answer 14

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Name of compoundFrequencies( cm -1 )Vibrationsmethoxybenzene 3060( m ) 2835( m ) 1498( s ) 1247( s ) 1040( s ) aromatic C−H stretch alkyl C−H stretch aromatic C=C stretch conjugatedC−O stretch saturated C−O stretchphenol 3370( s ) 3045( m ) 1595( s ) 1224( s ) O−H stretch aromatic C−H stretch aromatic C=C stretch conjugated C−O stretchbenzyl alcohol 3330( br,s ) 3030( m ) 2950( m ) 1454( m ) 1223( s ) O−H stretch aromatic C−H stretch alkyl C−H stretch aromatic C=C stretch C−O stretch

Answer 15

Expert Solution

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Interpretation Introduction

(c)

Interpretation:

The 2-phenyl propanal, 1-amino octane, phenylacetate, heptanoic acid, 2-methylpropanamide, 2-pentanone and acetophenone should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength so they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

Eis IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Laboratory Techniques in Organic Chemistry, Chapter 21, Problem 1Q

Answer 19

Interpretation Introduction

(c)

Interpretation:

The 2-phenyl propanal, 1-amino octane, phenylacetate, heptanoic acid, 2-methylpropanamide, 2-pentanone and acetophenone should be matched with the correct set of IR frequencies.

Concept introduction:

IR spectroscopy is spectroscopic method to identify the structure of organic compounds. When IR is passed through the sample, different bonds vibrate at different frequencies of IR by absorbing IR light. In IR spectrum energy in terms of wavenumber( cm-1 ) is the horizontal axis and intensity is the vertical axis.

As different molecules have different bonds of varying strength so they absorb IR light of different frequencies. This results in different absorption bands in the IR spectrum characteristic to that bond.

IR region is divided into 3 regions, near, mid and far IR region. The mid-IR region extends from 4000−600 cm-1 and it is the most important region as approximately all organic compounds absorb in this region.

The allowed vibrational energy levels for IR transition is as follows:

E=hνο(ν+1)

Where,

Eis IR energy absorbed by a molecule.

h is Planck's constant.

νο is zero point vibrational level.

ν is vibrational level with integer value of 1,2,3,4......

Answer 20

Expert Solution

Explanation of Solution

The absorption by a particular bond vibration appears as peak at definite positions in the IR spectrum irrespective of the compound in which they take place.

Frequency of peaks and their intensity is majorly based on the factors as follows:

Kind of vibration that is whether stretching or bending.
Bond order
Electronegativity difference
Molecular weight

On the basis of peak intensity, w is used to denote weakly intense peaks, s is used to denote strongly intense peak, m for medium intensity and b for broad peaks.

The correct match of the frequencies with the proper compound is tabulated as follows:

Laboratory Techniques in Organic Chemistry, Chapter 21, Problem 1Q