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Concept explainers
(a)
Find the void ratio of soil specimen.
(a)
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Answer to Problem 2.1P
The void ratio of soil is 0.76.
Explanation of Solution
Given information:
The mass (m) of the soil is
The volume (v) of the soil is
The moisture content (w) is 15%.
The specific gravity
Calculation:
Consider the unit weight of water
Calculate the moist unit weight of the soil
Calculate the dry unit weight of the soil
Calculate the void ratio (e) using the relation as shown below:
Hence, the void ratio of soil is 0.76.
(b)
Calculate the porosity of soil.
(b)
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Answer to Problem 2.1P
The porosity of soil is
Explanation of Solution
Calculation:
Refer to part (a).
The void ratio of soil is
Calculate the void ratio
Substitute
Hence, the porosity of soil is
(c)
Calculate the dry unit weight of soil.
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 2.1P
The dry unit weight of soil is
Explanation of Solution
Calculation:
Calculate the dry unit weight of the soil
Refer to part (a).
Base on result, the dry unit weight of the soil is
Thus, the dry unit weight of soil is
(d)
Calculate the moist unit weight of soil.
(d)
![Check Mark](/static/check-mark.png)
Answer to Problem 2.1P
The moist unit weight of soil is
Explanation of Solution
Calculation:
Calculate the moist unit weight of the soil
Refer to part (a).
Base on result, the dry unit weight of the soil is
Thus, the moist unit weight of soil is
(e)
Calculate the degree of saturation.
(e)
![Check Mark](/static/check-mark.png)
Answer to Problem 2.1P
The degree of saturation is
Explanation of Solution
Calculation:
Refer to part (a).
The void ratio of soil is
Calculate the degree of saturation
Hence, the degree of saturation is
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Chapter 2 Solutions
Principles of Foundation Engineering (MindTap Course List)
- A soil specimen has a volume of 0.05 m3 and a mass of 87.5 kg. Given: w = 15%, Gs = 2.68. Determine Porosity.arrow_forwarda. A soil specimen with volume of 0.60x10-4 m3 , weighs 0.105 kg. Its dry weight is 0.0802 kg, and Gs is 2.65. Compute • Water content m, % • Void ratio e and porosity n Degree of saturation Sr, %arrow_forwardA soil specimen has a volume of 0.05 m³ and a mass of 87.5 kg. Given: w= 15%, G,= 2.68. Determine a. Void ratioarrow_forward
- A sample of soil compacted according to the standard Proct or test has a density of 2.06 g/cm³ at 100% compaction and at an optimum water content of 14%. What is the dry unit weight? What is the dry unit weight at zero air-voids? If the voids become filled with water what would be the saturated unit weight? Assume Gs = 2.67 Air Water Solids Ma + - + M starrow_forwardPermeability tests were performed on a soil sample, under different void ratio and different temperatures and the following results were obtained. Test No. 1 2 Void ratio (e) 0.65 1.02 Temperature °℃ 25° 40⁰ Estimate the coefficient of permeability at a temperature of 20°C for a voids ratio of 0.80. Given the following physical properties of water: At 20°C, n = 10.09 × 10+ and p„ = 0.998 g/cm³ At 25°C, n = 8.95 × 104 g sec/cm² and p k(cm/s) 0.4x10 1.9x10-¹ At 40° C, n = 6.54 × 10-¹ g sec/cm² and p $0.997 g/cm³ = = 0.992 g/cm³arrow_forwardPermeability tests were performed on a soil sample, under different void ratio and different temperatures and the following results were obtained. Test No. 1 2 Void ratio Temperature °C (e) 0.65 1.02 25° 40⁰ Estimate the coefficient of permeability at a temperature of 20°C for a voids ratio of 0.80. Given the following physical properties of water: At 20°C, n = 10.09 × 10+ and p„ = 0.998 g/cm³ At 25°C, n = 8.95 × 104 g sec/cm² and p k(cm/s) 0.4x10 1.9x10¹ At 40° C, n = 6.54 × 10 g sec/cm² and p 8 0.997 g/cm³ = 0.992 g/cm³arrow_forward
- Problem 1 A sample of clay is brought back from the field and trimmed to a cylinder of the following dimensions: height = 600 mm, diameter = 150 mm. It weighs 200 N. The water content has been determined to be 12%. Assume a specific gravity of G = 2.7 for the soil particle, find the following parameters for the clay: a. Dry unit weight, Natural moist unit weight, Void ratio,Degree of saturation b. Volume of water to be added to increase the water content to 18% c. The mass of water to be added into this soil sample for full saturationarrow_forwardAsaparrow_forwardThe total volume of a soil specimen is 80,000 mm^3 and has a mass of 152 g. the dry mass of the specimen is 122g, and the density of the soil is 2.65 Mg/m^3. Compute the following index properties: (a) e; (b) n; (c) S; (d) ρt; and (e) ρd. Include phase diagrams.arrow_forward
- A fully saturated soil sample has a volume of 28 cc. The sample was dried in oven and the weight of the dry soil pat was found to be 48.76 g. Given G= 2.68. Determine the porosity in percent.arrow_forwardThe porosity of a soil sample is 35% and the specific gravity is 2.70. Calculate the following: a. Void Ratio b. Degree of Saturation c. Dry Unit Weight in Metric d. Saturated Unit Weight in Metricarrow_forward4. A clay sample has the following properties: .Porosity = 0.35 . Maximum void ratio = 0.85 . Minimum void ratio = 0.42 Specific gravity of soil solids = 2.72 • Moisture content = 62% Determine the dry unit weight of the soil in its natural state, in pounds per cubic foot (pcf).arrow_forward
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