What is the total energy of the Atwood's machine in the position shown am? If the blocks are released and m, falls through a distance of 1.00 m, kinetic and potential energy of each block, and what are their velocities?
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- a) The acceleration of a 5.0 kg box is 2.5 ms?. when a horizontal force is applied across a surface having a coefficient of friction of 0.5, as shown in Figure 3. a = 2.5 ms-2 7 kg Hk = 0.5 Figure 3 Find the work done over a distance of 25 cm by ix. the horizontal force the frictional force, and Х. xi. the net force. xi. what is the change in kinetic energy of the box?Suppose a force of 60 N is required to stretch and hold a spring 0.1 m from its equilibrium position. a. Assuming the spring obeys Hooke's law, find the spring constant k. b. How much work is required to compress the spring 0.6 m from its equilibrium position? c. How much work is required to stretch the spring 0.2 m from its equilibrium position? d. How much additional work is required to stretch the spring 0.1 m if it has already been stretched 0.1 m from its equilibrium? a. k= (Type an integer or a decimal.) b. Set up the integral that gives the work done in compressing the spring 0.6 m from its equilibrium position. Use decreasing limits of integration. (Type exact answers.) Find the work done in compressing the spring. The work is (Type an integer or a decimal.) c. Set up the integral that gives the work done in stretching the spring 0.2 m from its equilibrium position. Use increasing limits of integration. dx (Type exact answers.) Find the work done in stretching the spring. The…Resultant work on a translating body is equal to _____. a. Change in potential energy b. Change in kinetic energy c. Change in kinematics d. Change in kinetics
- ACTIVITY 5 ODL STEM 12A The energy consumed by a o.8okW electric drill is 45 kJ in 1. _hour/s. What is the speed of a 3.okg object when its kinetic energy is 5.0J? Express your answer in ft/s (feet/second) 2. 3. What is the speed of the same object in #2 if the object has a weight of o.225|b? What is the ratio of energy consumption of a person who moves minimally when his/her requirement in moving is 8 MJ of energy per day. Express your answer in Watts. 4.A learner with a mass of 60kg runs up a flight of stairs in 5 seconds.The height of the stairs is 300cm.a. Is work a vector or scalar quantity?b. Calculate the work done by the learner.2. What is the Kinetic Energy formula? a. What is the unit of measurements that each has to be in? b. What is the kinetic energy of a 200 kg roller coaster cart going 20 m/s?
- Remember to include given information, basic equations, calculations, and solutions with correct units for full credit. You are NOT to use kinematics unless otherwise stated. Captain America (100. kg) lunges vertically into the air, leaving the ground at 25.0 m/s and comes to a stop midair. a. How much work is done on him by gravity? b. Using the work–energy theorem, to what height did he reach?Dot. What is the scalar product ÷ Bifà = x² + yĵ and B = yî − xĵ? O A. 2xy OB. x² - y² o c. xyi - yx) O D. zero Work. Which of the following is the correct general expression for the work done by a constant force Fof magnitude F on an object of mass m which undergoes a displacement d with magnitude d? O A. Fd OB. mgd OC. F- mg OD. F.dQuestion has TWO parts Your answer needs to have 2 significant figure, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement. Part A - A 75 kg sprinter accelerates from 0 to 8.0 m/s in 5.0 s. What is the metabolic energy, in kJ (kiloJoules)? Part B - A 75 kg sprinter accelerates from 0 to 8.0 m/s in 5.0 s. What is the metabolic power, in kW (kiloWatts)?
- Compute the kinetic energy of an 1800 lb automobile traveling at 30 mi/hr, How many times as great is the kinetic energy if the velocity is doubled. Ans. Four times4. Always begin by writing the general form of an equation. Insert numbers and units. Remember to show all work (and units). Present the solution well organized and clearly. answer should be: a) F=566N, FN=1.13x103N just need an explanation on how to get to this.Q1/If an applied force varies with position according to Fy = 3X* + 2t* + t + 4, where X in meter .How much work is done by this force on an object that moves from x= 5m to x=10 m?