What is the low frequency break point due to the capacitor Cs for this BJT amplifier (Amplifier A)? Amplifier A: A common-emitter, voltage divider bias circuit with bypass capacitor with the following values: Vcc = 25.6V, Rs = 80O, R1 = 82k 2, R2 = 12.5k Q, Rc = 2.2k Q, RE = 1.1k Q, B = 100, Cs = 0.5uF, Cc = 0.2uF, CE = 10uF, and R = 5.2k Q.

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Question 2
What is the low frequency break point due to the capacitor Cs for this BJT amplifier (Amplifier A)?
Amplifier A:
A common-emitter, voltage divider bias circuit with bypass capacitor with the following values: Vcc = 25.6V, Rs = 80O, R1 = 82k 2, R2 = 12.5k Q, Rc = 2.2k Q, RE =
1.1k Q, B = 100, Cs = 0.5uF, Cc = 0.2uF, CĘ = 10uF, and RL = 5.2k 2.
O 4 Hz
O 4.269 Hz
O 25 Hz
30.6 Hz
Transcribed Image Text:Question 2 What is the low frequency break point due to the capacitor Cs for this BJT amplifier (Amplifier A)? Amplifier A: A common-emitter, voltage divider bias circuit with bypass capacitor with the following values: Vcc = 25.6V, Rs = 80O, R1 = 82k 2, R2 = 12.5k Q, Rc = 2.2k Q, RE = 1.1k Q, B = 100, Cs = 0.5uF, Cc = 0.2uF, CĘ = 10uF, and RL = 5.2k 2. O 4 Hz O 4.269 Hz O 25 Hz 30.6 Hz
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