) water hardness of each trial and average ppm with calculation, please. Hard Water Trial 1 Hard Water Trial 2 Hard Water Trial 3 Initial Syringe Reading 1.0ml 1.0ml 1.0ml Final Syringe Reading 0.88ml 0.84ml 0.85ml Volume of EDTA Consumed 0.12ml 0.16ml 0.15ml Water Hardness ppm CaCO3 Average ppm
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Q) water hardness of each trial and average ppm with calculation, please.
|
Hard Water Trial 1 |
Hard Water Trial 2 |
Hard Water Trial 3 |
Initial Syringe Reading |
1.0ml |
1.0ml |
1.0ml |
Final Syringe Reading |
0.88ml |
0.84ml |
0.85ml |
Volume of EDTA Consumed |
0.12ml |
0.16ml |
0.15ml |
Water Hardness ppm CaCO3 |
|
|
|
Average ppm
|
|
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- Concentration of Acetic Acid in a Vinegar Solution. Average molarity of NaOH Volume HC₂H30₂ sample Final buret reading Initial buret reading Volume NaOH (Show all units and all calculations) Molarity of HC₂H30₂ (unrounded) Average molarity of HC₂H302 (unrounded) Deviations Average deviation Best estimate for molarity of HC₂H302 Average mass percent HC₂H302 46.4mL Oml Ran out of Base ↓ ↓ ↓ ↓ 10.014 HOA je beart giov isults weari?! ferottelucuny Cambia) 10 Kousad Question 1. A Rolaids tablet contains calcium carbonate that neutralizes stomach acid. If 44.55 mL of 0.448 M hydrochloric acid is required to neutralize one tablet, how many milligrams of calcium carbonate are in a Rolaids tablet? CaCO, (s) + 2HCl(aq) → CaCl₂ (aq) + H₂O (1) + CO₂ (g)102 Experiment 12 Determination of Molar Mass by the Freezing Point Depression Method 2. The equation ATf = Kfm is only strictly applicable to very solutions. 3. The f.p. lowering (AT;) only depends on the molality and is independent of the nature of the solute. This is known as a property. 4. A solid is melted then allowed to cool and the temperature of the liquid is recorded every 2 minutes. According to the plot below, the most probable f.p. of the solid is °C. 75.5 75.0 74.5 74.0 73.5 73.0 72.5 72.0 71.5 71.0 70.5 4 6. 10 12 14 16 18 20 22 24 26 Time (min) Temperature (°C) (Figure created by David Sarno.) р. 102A. Standardlzatlon of thlosulfate solutlon Trial 1 Trial 2 Trial 3 Initial volume of thiosulfate (mL) 0.00 20.05 2.3 Final volume of thiosulfate (mL) 20.05 40.05 22.15 Volume of thiosulfate used (mL) Molarity of thiosulfate Average Molarity of thiosulfate Calculate the molarity of the thiosulfate solution using the formula: 6 mmol S20,²- 1 mmol 10, Ms,0,2- 0.004167 M 10,- 20.00 ml Vol S20,²- used (mL)
- Based on the table below, calculate F-factor and X in the water sample. (Berdasarkan jadual di bawah, kirakan faktor-F dan X dalam sampel air.) 7. Abs nitrite concentration Standard 0.032 0.4ppm Xppm Water sample 0.067Density of solution:Trial 1: 1.2 g/mLTrial 2: 1.2 g/mLTrial 3: 1.2 g/mL Average density = 1.2 g/mL What is the relative average deviaion, %?Mass of KIO3 used0.4125 gVolume of KIO3 solution prepared 100.0 mLVolume of unknown ascorbic acid solution 15.00 mLVolume of KIO3 solution used to reach endpoint13.25 mL1. Calculate the molarity of the KIO3 solution prepared.2. Calculate the molarity of ascorbic acid in the unknown solution.3. Assuming the density of the unknown solution is 1.00 g/mL; calculate the percentage by mass of ascorbic acid (C6H806) in each sample.Answers: (1) 0.01928 M (2) 0.05108 M (3) 0.300 %
- SALT SOLUTION: Trial 1: Volume: 25 mLMass of 25mL solution: 29.824 gDensity: 1.2 g/mL Trial 2:Volume: 25 mLMass of 25 mL solution: 29.855 gDensity: 1.2 g/mL Trial 3:Volume: 25 mLMass of 25 mL solution: 29.816 gDensity: 1.2 g/mL METAL BAR: Method I - Trial 1:Mass of metal bar: 57.063 gVolume of metal bar: 6.7 cm^3Density of bar: 8.5 g/cm^3 Trial 2:Mass of metal bar: 57.063 gVolume of metal bar: 6.0 cm^3Density of bar: 9.5 g/cm^3 Trial 3:Mass of metal bar: 57.063 gVolume of metal bar: 6.0 cm^3Density of bar: 9.5 g/cm^3 Method 2 - Trial 1:Dimensions: diameter = 1.20 cm, height = 4.91 cmMass of metal bar: 57.063 gVolume of metal bar: 5.55 cm^3Density of bar: 10.3 g/cm^3 Trial 2:Dimensions: diameter = 1.20 cm, height = 4.95 cmMass of metal bar: 57.063 gVolume of metal bar: 5.60 cm^3Density of bar: 10.2 g/cm^3 Trial 3:Dimensions: diameter = 1.20 cm, height = 4.95 cmMass of metal bar: 57.063 gVolume of metal bar: 5.60 cm^3Density of bar: 10.2 g/cm^3 QUESTION - From your data, calculate the…STANDARDIZATION OF NAOH SOLUTION A 0.4047 g sample of primary standard grade potassium hydrogen phthalate (MM = 204.23) was dissolved in distilled H2O. The solution required 22.42 mL of the NaOH solution to reach the phenolphthalein end point. a.) Calculate the number of mmoles of KHP. b.) How many moles of NaOH will react with the KHP dissolved in water? c.) Calculate the molarity of the NaOH solution.A stock solution of approximately 7.7x10^-5 molar will be provided in lab. Determine the volumes of each solution needed to prepare 50.00 mL of standard solutions of concentration 0.600x10^-5molar, 1.20x10^-5molar, 2.40x10^-5molar, and 3.00x10^-5molar. Round the calculated volumes to thenearest 0.1mL.
- Concentration of the KSCN stock solution, M Volume of the KSCN stock solution, mL Initial molar concentration of SCN in a 50-ml flask, M PART A. Establishing the Beer's Law Coefficient: blank 0 0 solution 2 1.00×10-³ 2.00 solution 3 1.00×10-3 5.00 solution 4 1.00×10-³ 10.00 solution 5 1.00-10-3 15.00chools.schoology.com/common-assessment-delivery/start/4573067641?action%3Donresume&submissionld%3547892539 150 140 130 120 110 100 NANO 90 80 70 60 NH C Ka Náci 50 40 30 20 KCIÓ, 10 Cez(so 10 20 30 40 50 60 70 80 90 100 Temperature (C) The compound with the least solubility at 50 °C is OKI O NANO3 O KNO3 O NH3 O NH&CI O KCI O NaCI O KCIO3 O Cex(SOa)a DELL & Grams of solute102 Experiment 12 Determination of Molar Mass by the Freezing Point Depression Method 2. The equation ATf Kem is only strictly applicable to very solutions. 3. The f.p. lowering (AT) only depends on the molality and is independent of the nature of the solute. This is known as a - property. 4. A solid is melted then allowed to cool and the temperature of the liquid is recorded every 2 minutes. According to the plot below, the most probable f.p. of the solid is. °C. Temperature (°C) 75.5 75.0 74.5 74.0 73.5 73.0 72.5 72.0 71.5 71.0 70.5 0 2 4 6 8 10 12 14 Time (min) 16 18 20 22 24 26 (Figure created by David Sarno.