Use exhaustive key search to decrypt the following ciphertext, which was encrypted using a Shift Cipher: BEEAKFYDJXUQYHYJIQRYHTYJIQFBQDUYJIIKFUHCQD.
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- Suppose that in a long ciphertext message the letter occurred most frequently, followed in frequency by. Using the fact that in the -letter alphabet, described in Example, "blank" occurs most frequently, followed in frequency by, read the portion of the message enciphered using an affine mapping on. Write out the affine mapping and its inverse. Example 2 Translation Cipher Associate the letters of the "alphabet" with the integers. Let and define the mapping by where is the key, the number of positions from the plaintext to the ciphertext. If our alphabet consists of through, in natural order, followed by a blank, then we have "letters" that we associate with the integers as follows:Encrypt the message APPLES AND ORANGES using a shift cipher with key k = 13.Encrypt the message KILLTHEBEAST using shift cipher with K=18.
- Decrypt the message "XMJQYJWNSUQFHJ" which was encrypted with a Caesar cipher with a shift of 5 (A to F). Give your response in all caps with no spaces.Suppose that the ciphertext ERC WYJJMGMIRXPC EHZERGIH XIGLRSPSKC MW MRHMWXMRKYMWLEFPI JVSQ QEKMG was produced by encrypting a plaintext message using a shift cipher. What is the original plaintext?Describe the family of shift ciphers as a cryptosytem.
- (Hill Cipher) Decrypt the following cipher text: YZZN Using the key K =The ciphertext OIKYWVHBX was produced by encrypting a plaintext message using the Vigen`ere cipher with key HOT. What is the plaintext message?Determine whether there is a key for which the enciphering function for the shift cipher is the same as the deciphering function.
- Use the RSA cipher with public key (n, e) = (713, 43) to encrypt the word "TEE." Start by encoding the letters of the word "TEE" into their numeric equivalents. Assume the letters of the alphabet are encoded as follows: A = 01, 8 = 02, C = 03, ..., Z = 26. Since the code for T is 20 and since e = 43 = 32 + 8 + 2 + 1, the first letter of the encrypted message is found by computing 2043 mod 713. 20¹a (mod 713) 20² Eb (mod 713) 204 c (mod 713) 208 d (mod 713) 2032 = f (mod 713) 2016 e (mod 713) b = The result is that a = C = d = e = and f = Thus, 2043 mod 713 = (a · b. d. f) mod 713 = So the first number in the encrypted message is Repeat these computations for each letter to find the complete encrypted message and enter your answer below. (Enter the message as a sequence of integer triples separated by a single space, where each triple is written using a fixed number of digits: 001 for 1, 002 for 2, ..., 099 for 99.)Suppose the RSA cryptosystem is used with public key (35, 7). What is the corresponding cipher text when the plain text "2" is sent? O 23 15 12 O 83. Decrypt the letters XMMIFZXQFLKP if it was encrypted using an alphabetic Caesar shift cipher with shift 23 right. Complete the table and write the decrypted message below. Original A BCDEFGHIJ KLMN 0 PQR STUV W XY Z Maps to Decrypted message for XMMIFZXQFLK: