The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 Code: # Split input into 2 parts: name and age parts = input ().split() name = parts [0] while name != '-1': # FIXME: The following line will throw ValueError exception. # Insert try/except blocks to catch the exception. age = int(parts [1]) + 1 print (f' {name} {age}') # Get next line parts = input ().split() name = parts [0]

The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 Code: # Split input into 2 parts: name and age parts = input ().split() name = parts [0] while name != '-1': # FIXME: The following line will throw ValueError exception. # Insert try/except blocks to catch the exception. age = int(parts [1]) + 1 print (f' {name} {age}') # Get next line parts = input ().split() name = parts [0]

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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The given program reads a list of single-word first names and ages (ending with-1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 -----------This is what I need to fill out---------- # Split input into 2 parts: name and ageparts = input().split()name = parts[0]while name != '-1':# FIXME: The following line will throw ValueError exception.# Insert try/except blocks to catch the exception.age = int(parts[1]) + 1print('{} {}'.format(name, age))# Get next lineparts = input().split()name = parts[0]
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 Here is the code that needs to be corrected: # Split input into 2 parts: name and age#parts = input().split()#name = parts[0]#while name != '-1':# FIXME: The following line will throw ValueError exception.# Insert try/except blocks to catch the exception.#age = int(parts[1]) + 1# print('{} {}'.format(name, age))# Split input into 2 parts: name and ageparts = input().split()#namename = parts[0]#if user enters -1while name != '-1':#try blocktry:age = int(parts[1]) + 1#exceptionexcept Exception as ex:#set age equal to 0age = 0# Get next…
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 main.cpp #include <string>#include <iostream> using namespace std; int main(int argc, char* argv[]) {string inputName;int age;// Set exception mask for cin streamcin.exceptions(ios::failbit); cin >> inputName;while(inputName != "-1") {// FIXME: The following line will throw an ios_base::failure.// Insert a try/catch statement to catch the exception.// Clear cin's failbit to put cin in a useable state.cin >> age;cout << inputName << " " << (age + 1) << endl; cin >> inputName;}return 0;}
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The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 √
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Java programming See attached The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch statement to catch java.util.InputMismatchException, and output 0 for the age. import java.util.Scanner;import java.util.InputMismatchException; public class NameAgeChecker { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); String inputName; int age; inputName = scnr.next(); while (!inputName.equals("-1")) { // FIXME: The following line will throw an InputMismatchException. // Insert a try/catch statement to catch the exception. age = scnr.nextInt(); System.out.println(inputName + " " + (age + 1)); inputName = scnr.next(); } }}
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch statement to catch java.util.InputMismatchException, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 NameAgeChecker.java import java.util.Scanner;import java.util.InputMismatchException; public class NameAgeChecker {public static void main(String[] args) {Scanner scnr = new Scanner(System.in); String inputName;int age;inputName = scnr.next();while (!inputName.equals("-1")) {// FIXME: The following line will throw an InputMismatchException.// Insert a try/catch statement to catch the exception.age = scnr.nextInt();System.out.println(inputName + " " + (age + 1));inputName = scnr.next();}}}
s and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 419894.2696446.qx3zqy7 #include <string>#include <iostream> using namespace std; int main() { string inputName; int age; // Set exception mask for cin stream cin.exceptions(ios::failbit); cin >> inputName; while(inputName != "-1") { // FIXME: The following line will throw an ios_base::failure. // Insert a try/catch statement to catch the exception. // Clear cin's failbit to put cin in a useable state. cin >> age; cout << inputName << " " << (age + 1) << endl; cin >> inputName; } return 0;}
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