The following data are available from orthogonal cutting experiments. In both cases, depth of cut (feed) to = 0.13 mm, width of cut w = 2.5 mm, rake angle a = -5°, and cutting speed V = 2 m/s. a. Determine the shear angle o, friction coefficient u, shear stress t and shear strain y on the shear plane, chip velocity Vc and shear velocity Vs, as well as the unit energies. Compare the results. Parameters Chip thickness, tc, mm Cutting force, Fe, N Thrust force, F₁, N Work piece Materials Aluminum 0.23 430 280 Parameters Flow strength (Y₁, MPa) Thermal diffusivity; K, mm²/s Volumetric specific heat; pc, N/mm²°C Steel 0.58 890 800 b. Estimate the temperatures for the conditions of last problem for the following work piece properties. Work piece Materials Aluminum Steel 120 523 97 14 2.6 3.3

The following data are available from orthogonal cutting experiments. In both cases, depth of cut (feed) to = 0.13 mm, width of cut w = 2.5 mm, rake angle a = -5°, and cutting speed V = 2 m/s. a. Determine the shear angle o, friction coefficient u, shear stress t and shear strain y on the shear plane, chip velocity Vc and shear velocity Vs, as well as the unit energies. Compare the results. Parameters Chip thickness, tc, mm Cutting force, Fe, N Thrust force, F₁, N Work piece Materials Aluminum 0.23 430 280 Parameters Flow strength (Y₁, MPa) Thermal diffusivity; K, mm²/s Volumetric specific heat; pc, N/mm²°C Steel 0.58 890 800 b. Estimate the temperatures for the conditions of last problem for the following work piece properties. Work piece Materials Aluminum Steel 120 523 97 14 2.6 3.3

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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3) The following data are available from orthogonal cutting experiment, Depth of cut t, = 0.13 mm, width of cut w = 2.5 mm, rake angle a = -5°, cutting speed v = 2 m/s, Chip thickness, t= 0.23 mm, cutting force, F. = 430 N, thrust force, F = 280 N. Determine the following: Shear angle Friction Coefficient u (using F= µ N) Shear Stress t,S Shear strain y on the shear plane. Power required to perform the operation. Gross power required if the efficiency of the machine is 85%. Specific Energy, Ut
Question 4. The following data are available from orthogonal cutting experiments. The depth of cut (feed) to = 0.13 mm, width of cut b = 2.5 mm, rake angle a = - 5°, and cutting speed V = 2 m/s. Chip thickness, t. (mm) = 0.23 Cutting force, F. (N) = 430 Thrust force, F; (N) = 280 Determine the shear angle ð, friction coefficient u , shear stress t, shear strain y on the shear plane, chip velocity Ve, and shear velocity Vs, as well as energies uf ,Ug, and u
Note: Read the question carefully and give me right solutions according to the question. In orthogonal cutting of steel tube of 150 mm diameter and 2 mm thick, the cutting force was 130 kg and feed force was 35 kg for chip thickness of 0.3mm. The orthogonal cut was taken at 60 meter per minute with a feed of 0.14 mm/rev. If the back rack angle of the cutting tool was - 8 o (minus 8 degree), then calculate the shear strain and strain energy per unit volume.
In a turning operation, cutting speed =200 m/min; feed = 0.25mm mm/rev, and depth of cut = 4.00mm Thermal diffusivity of the work material = 20m mm^2/s and volumetric specific heat =3.5(10^ -3 )J/mm^ 3 -C If the temperature increase above ambient temperature (20degreesC) is the angle measured by a tool-chip thermocouple to be 700degreesC, determine the specific energy for the work material in this operation.
In an orthogonal cutting test with a bar of 75 mm diameter is reduced to 73 mm by using a HSS tool with arake angle  = 10o, following observations were made: length of the chip, lc = 69.44 mm, cutting ratio r =0.3, the horizontal component of the cutting force, FH = 1450 N, and the vertical component of the cuttingforce, FV = 850 N. The various parameters recorded in this cutting operation are: depth of cut, d = 2 mm;feed rate, f = 0.3 mm/rev, cutting speed, V = 60 m/min. Using Merchant’s theory calculate the following:1) Friction force along rake face2) Normal force acting on rake face3) Shear force along the shear plane4) Normal force acting on shear plane5) The percentage error in shear angle predicted by Merchant’s theory6) Shear velocity7) Chip velocity8) Total work done9) The shear work proportion out of the total work done10) The friction work proportion out of the total work done
2. The following data was obtained from an orthogonal cutting test: Rake angle = 20° Cutting speed = 100 m/min Chip length before cutting = 29.4 mm Chip length after cutting = 12.9 mm Vertical cutting force 1050 N Horizontal cutting force = 630 N Using Merchant's analysis, calculate (a) resultant force (c) friction force and friction angle (b) shear plane angle (d) total work done
2) In an orthogonal cutting operation, the cutting tool has a rake angle = 20°. The chip thickness before the cut = 0.25 mm. If the cutting force and thrust force are measured during an orthogonal cutting operation with values, Fc = 1450 N and Ft = 1990 N. The width of the orthogonal cutting operation w = 2.5 mm. the friction angle B is = 79.91° Determine: The Shear Angle The Shear Strain The Shear Strength of the material The Force of Friction
Rake angle=20 degree, Depth of cut=6 mm, Feed rate =0.25mm/rev,Cutting speed=0.6 m/s, chip length before cutting=29.4mm, vertical cutting force= 1050 NHorizontal cutting force=630, chip length after cutting=12.9Using Merchant’s analysis calculate(a) direction and magnitude of resultant force(b) friction force and friction angle(c) shear plane angle
An orthogonal cutting operation is being carried out under the following conditions: t0-D0,38 mnm, tc-0,65 mm, width of the cut- 2.5 mm, V= 3.5 m/s, rake angle=D 6, Fc= 515 N, and Ft= 210 N. Calculate the percentage of the total energy that is dissipated in the shear plane. The power input in cutting= F.V Power for shearing-F,V, IcCOs a tc tan ø = 1 –r. sin a F, = F.cos o – F, sin o %3D cos a V cos( – a)
In turning of stales steel alloy, 1100 mm length and 400 mm diameter, the Feed was 0.35 mm/rev, and depth of cut = 2.5 mm. The tool used in this cutting is cemented carbide tool where Taylor tool life parameters are n = 0.24 and C = 450 (tool life (min) and cutting speed (m/min). Compute the cutting speed that will allow the tool life to be 10% longer than the machining time for this part.
across the surface and (b) the maximum metal removal rate during cutting A slab milling operation is performed on the top surface of a steel rectangular workpiece 12.0 in long by 2.5 in wide. The helical milling cutter, which has a 3.0 in diameter and ten teeth, is set up to overhang the width of the part on both sides. Cutting speed is 125 ft/min, feed is 0.006 in/tooth, and depth of cut = 0.300 in. Determine (a) the actual machining time to make one pass across the surface and (b) the maximum metal removal rate during the cut. (c) If an additional approach distance of 0.5 in is provided at the beginning of the pass (before cutting begins), and an overtravel distance is provided at the end of the pass equal to the cutter radius plus 0.5 in, what is the duration of the feed motion.
A cylindrical mild steel work piece of Ø55 X 200mm undergoes a turning operation on a lathe machine to reduce the diameter to Ø 45mm. The cutting parameters are 23 m/minute, 0.3 mm/ revolution and 0.5 mm are cutting speed, feed and depth of cut respectively. Determine the following. i) Time for single pass (minutes). ii) Find number of passes required to reduce the diameter from Ø55 to Ø45mm. iii) Total time required to complete the turning operation in minutes (Tfinal).