Start around spindle Floor h E The apparatus used in the lab is shown above. The rotational inertia for two masses rotating about a center point is I = 2MR² R=12.9 cm (convert to meters!) D=14 millimeters (divide by 2 to get radius, r, and convert to meters!) m = 200 grams (convert to kilograms!) h = 0.93 meters t = 7.6 seconds <-- Time for the mass to fall to h meters to the ground The mass and rotational inertia of the connecting rod (between the masses) is negligible. What is the TENSION in the string that is attached to the mass, m? Give your answer in m/s² to two decimal places.

icon
Related questions
Question
Start
around spindle
Floor
h
E
The apparatus used in the lab is shown above. The rotational inertia for two
masses rotating about a center point is I = 2MR²
R=12.9 cm (convert to meters!)
D=14 millimeters (divide by 2 to get radius, r, and convert to meters!)
m = 200 grams (convert to kilograms!)
h = 0.93 meters
t = 7.6 seconds <-- Time for the mass to fall to h meters to the ground
The mass and rotational inertia of the connecting rod (between the masses) is
negligible.
What is the TENSION in the string that is attached to the mass, m?
Give your answer in m/s² to two decimal places.
Transcribed Image Text:Start around spindle Floor h E The apparatus used in the lab is shown above. The rotational inertia for two masses rotating about a center point is I = 2MR² R=12.9 cm (convert to meters!) D=14 millimeters (divide by 2 to get radius, r, and convert to meters!) m = 200 grams (convert to kilograms!) h = 0.93 meters t = 7.6 seconds <-- Time for the mass to fall to h meters to the ground The mass and rotational inertia of the connecting rod (between the masses) is negligible. What is the TENSION in the string that is attached to the mass, m? Give your answer in m/s² to two decimal places.
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer