Recall that with the CSMA/CD protocol, the adapter waits K*512 bit-times after a collision, where K is drawn randomly a. For K = 100, how long does the adapter wait until returning to Step 2 (carrier sense to re- attempt transmission) for a 1 Mbps broadcast channel? For a 1 Gbps broadcast channel? i. 512*10^-4 seconds for 1Mbps and 512*10^-7 seconds for 1Gbps. ii. 512*10^-6 seconds for 1Mbps and 512*10^-9 seconds for 1Gbps. iii. 512*10^-9 seconds for 1Mbps and 512*10^-6 seconds for 1Gbps. iv. 512*10^-7 seconds for 1Mbps and 512*10^-4 seconds for 1Gbps. b. The higher the transmission rate of an interface, the sooner it will be able to retry a retransmission. True or False. i. True Rolan

Operations Research : Applications and Algorithms
4th Edition
ISBN:9780534380588
Author:Wayne L. Winston
Publisher:Wayne L. Winston
Chapter20: Queuing Theory
Section20.10: Exponential Queues In Series And Open Queuing Networks
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Recall that with the CSMA/CD protocol, the adapter waits K*512 bit-times after a collision, where K is drawn randomly.
a. For K = 100, how long does the adapter wait until returning to Step 2 (carrier sense to re-
attempt transmission) for a 1 Mbps broadcast channel? For a 1 Gbps broadcast channel?
i. 512*10^-4 seconds for 1Mbps and 512*10^-7 seconds for 1Gbps.
ii. 512*10^-6 seconds for 1Mbps and 512*10^-9 seconds for 1Gbps.
iii. 512*10^-9 seconds for 1Mbps and 512*10^-6 seconds for 1Gbps.
iv. 512*10^-7 seconds for 1Mbps and 512*10^-4 seconds for 1Gbps.
b. The higher the transmission rate of an interface, the sooner it will be able to retry a
retransmission. True or False.
i. True
ii. False
Transcribed Image Text:Recall that with the CSMA/CD protocol, the adapter waits K*512 bit-times after a collision, where K is drawn randomly. a. For K = 100, how long does the adapter wait until returning to Step 2 (carrier sense to re- attempt transmission) for a 1 Mbps broadcast channel? For a 1 Gbps broadcast channel? i. 512*10^-4 seconds for 1Mbps and 512*10^-7 seconds for 1Gbps. ii. 512*10^-6 seconds for 1Mbps and 512*10^-9 seconds for 1Gbps. iii. 512*10^-9 seconds for 1Mbps and 512*10^-6 seconds for 1Gbps. iv. 512*10^-7 seconds for 1Mbps and 512*10^-4 seconds for 1Gbps. b. The higher the transmission rate of an interface, the sooner it will be able to retry a retransmission. True or False. i. True ii. False
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