following project duration. Additionally, calculate the following: Normal durationcost, Normal duration, Shortest duration cost, and Shortest duration. Note: Use theprovided sample of the table as a guide in your solution.Q4) Using the time-cost trade-off concepts, determine the logical steps to reduce theST.CostDifference $/DayTimeCrashCost(),DifferenceNormalCost ($)Normal CrashTime(5)Time001.3.ID0002501.5509.7.B.C.D.5.0098.6.6.5.000E.F.G.3.00991.ProjectDuration3501.3CostforTotalCostH.3CostperDay3.DaysCycleTable sample:ActivityToK.Can beShortened ShortenedCycle#3Shorten

Answered: Image /qna-images/answer/bb7680eb-7a65-47fc-843c-8dd8ea9edd59.jpg

Q4) Using the time-cost trade-off concepts, determine the logical steps to reduce the following project duration. Additionally, calculate the following: Normal duration cost, Normal duration, Shortest duration cost, and Shortest duration. Note: Use the provided sample of the table as a guide in your solution. ST. Crash Cost Cost Difference S$/Day Time Normal Normal Crash Time Act. Difference ID Time Cost ($) (%$4) () A 1. 009 B. 7. 550 C. 250 D. 8. 6. 009 E. G. 9. 6. to 00 H. 3. 350 3. K. Table sample: Activity To Cost for Cycle Cost per Day Project Duration Total Days Shortened Shortened Can be Cycle Cost #3 Shorten 1335o31213

Q4) Using the time-cost trade-off concepts, determine the logical steps to reduce the following project duration. Additionally, calculate the following: Normal duration cost, Normal duration, Shortest duration cost, and Shortest duration. Note: Use the provided sample of the table as a guide in your solution. ST. Crash Cost Cost Difference S$/Day Time Normal Normal Crash Time Act. Difference ID Time Cost ($) (%$4) () A 1. 009 B. 7. 550 C. 250 D. 8. 6. 009 E. G. 9. 6. to 00 H. 3. 350 3. K. Table sample: Activity To Cost for Cycle Cost per Day Project Duration Total Days Shortened Shortened Can be Cycle Cost #3 Shorten 1335o31213

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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1. For the following schedule draw the node network, perform the CPM calculations, mark the critical path, and complete the table below. Then impose a finish date of 20 days and a finish date of 25 days, and recalculate the CPM and the values in the table. IPA TF Act A B C D E F G Dur 2 4 6 95 9 7 3 A A, B B B B, C C, D, E, F ES EF LS LF FF
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The network of a small construction project awarded to a contractor is shown in the following figure. The normal duration, crash duration, normal cost, and crash cost of all the activities are shown in the table. The indirect cost incurred by the contractor is INR 5000 per day. Normal Crash Normal Activity Duration Duration (days) 6. Crash Cost Cost (days) (NR) (INR) 15000 25000 4 Q 6000 12000 3 8000 9500 3 7000 10000 3 2 6000 9000 U 2 1 4000 6000 V 4 20000 28000 If the project is targeted for completion in 16 days, the total cost (in INR) to be incurred by the contractor would be RST
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7. An activity-on-node diagram for a construction project is given below. (Activity letters and durations are shown in each node circle.) What is the float time for activity 'G’? (start) end
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