= Q₁ = -0.10 μC is located at the origin. 2 +0.10 μC is located on the positive x axis at x = 1.0 m. Which of the following is true of the force on Q₁ due to Q₂? (a) It is attractive and directed in the +x direction. (b) It is attractive and directed in the -x direction. (c) It is repulsive and directed in the +x direction. (d) It is repulsive and directed in the -x direction.
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- A particle with charge q on the negative x axis and a second particle with charge 2q on the positive x axis are each a distance d from the origin. Where should a third particle with charge 3q be placed so that the magnitude of the electric field at the origin is zero?Q1 = -0.10 µC is located at the origin. Q2 = +0.10 µC is located on the positive x axis at x = 1.0 m. Which of the following is true of the force on Q, due to Q2? (a) It is attractive and directed in the +x direction. (b) It is attractive and directed in the -x direction. (c) It is repulsive and directed in the +x direction. (d) It is repulsive and directed in the –x direction.Two horizontal plates of opposite charge form a constant electric field = 1000 N/C directed vertically downwards. An electron of mass me and charge e* is fired horizontally with velocity v = 0.1c, where c = 3.00 x 108 m/s between the plates. Calculate the electron's acceleration. If the plates have length 1 m, find the electron's deflection from the horizontal when it emerges.
- There is a negative charged particle of 0.32 C in the free space. (a) What are the magnitude and direction of the electric field 2 m away from the particle? (b) What are the magnitude and direction of the electric force when an electron is placed 2 m away from this particle?A particle possessing ?=9.25 μCq=9.25 μC of charge and a mass of ?=4.55 gm=4.55 g is fired at a speed of ?=357 cm/sv=357 cm/s between two horizontal charged plates of length ?=44.7 cm. Assume that the electric field between the plates is uniform and has a constant value of ?=965 N/C,E=965 N/C, directed upwards. Calculate the distance ?y by which the charge falls below a straight‑line path when it reaches the end of the plates. Assume a gravitational acceleration of ?=9.81m/s2.(For a electron) moves horizontally with a speed of 1.55 X 10^6 m/s between two horizontal parallel plates(positive plate is on top). The plates have a length of 11.9 cm, and a plate separation that allows a charged particle to escape even after being deflected. The magnitude of the electric field within the plates is 155 N/C. Calculate the final velocity of an electron as it leaves the plates.
- The friends now try a homework problem. Consider an electron, of charge magnitude e = 1.602 × 10-¹⁹ C and mass me = 9.11 x 10-31 kg, moving in an elect field with an electric field magnitude E = 7 x 10² N/C, similar to what Thana observed in the simulation. Let the leng the plates be L = 50 cm, and the distance between them be d = 20 cm. Find the maximum speed, v, the electron co be moving if it enters the space halfway between and parallel to the two plates to just barely strike one of the plates 7.01e+06 X m/s If the field is pointing upward, which plate will Thana conclude the electron strikes at this speed? The lower plate, because the electron is negatively charged. The lower plate, because the electron is attracted to the negative plate. The upper plate, because we are only considering the magnitude of the electron charge, and magnitudes are always positive. O The upper plate, because the electron charge magnitude is positive.An electron and a proton, each starting from rest, are accelerated by the same uniform electric field of 200 N/C. Determine the distance and time for each particle to acquire a kinetic energy of 3.2 × 10−16 J.How far apart should two protons be if the electrical force of repulsion on each one is equal to its weight on the earth? (k = 1/4m² = 9. 9.0x109 Nm²/C2,e-1.6x10-19, m = 1.67 x 10-27kg) cm
- A particle leaves the origin with a speed of 3.5 106 m/s at 28 degrees to the positive x axis. It moves in a uniform electric field directed along positive y axis. Find Ey such that the particle will cross the x axis at x = 1.5 cm if the particle is an electronTwo horizontal plates of opposite charge form a constant electric field = 1000 N/C directed vertically downwards. An electron of mass m, and charge eis fired horizontally with velocity v = 0.1c, where c = 3.00 x 10³ m/s between the plates. Calculate the electron's acceleration. If the plates have length 1 m, find the electron's deflection from the horizontal when it emerges.In figure 2, an upwardly oriented uniform electric field E⃗ of a magnitude of 2.0 × 103 N / C has been established between two horizontal plates by charging the lower plate positively and the upper plate negatively. The plates have a length L = 10.0 cm, and they are at a distance of d = 2.0 cm. An electron is sent between the plates from the left end of the lower plate. The initial velocity ⃗v0 of the electron forms an angle θ = 45◦ with the lower plate, and its magnitude is 6.0 × 106 m / s (a) Will the electron touch one of the plates? (b) If so, determine which one. Then find how far horizontally from the left end the electron will strike.