point) Approximate cos(4.6) using a quadratic approximation: First note that cos(4.6) cos(3/2). Let f(x) = cos(x). Then, f'(x) = -sinx and f"(x) = -cosx Let a = 3/2. Then f' (3/2) = -sin(3pi/2) and f" (3/2) = -cos(3pi/2) Q(x), the quadratic approximation to cos(x) at a = 3/2 is: Q(x) = Use Q(x) to approximate cos(4.6). cos(4.6)~
point) Approximate cos(4.6) using a quadratic approximation: First note that cos(4.6) cos(3/2). Let f(x) = cos(x). Then, f'(x) = -sinx and f"(x) = -cosx Let a = 3/2. Then f' (3/2) = -sin(3pi/2) and f" (3/2) = -cos(3pi/2) Q(x), the quadratic approximation to cos(x) at a = 3/2 is: Q(x) = Use Q(x) to approximate cos(4.6). cos(4.6)~
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter4: Calculating The Derivative
Section4.CR: Chapter 4 Review
Problem 2CR: Determine whether each of the following statements is true or false, and explain why. The derivative...
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![1 point) Approximate cos(4.6) using a quadratic approximation:
First note that cos(4.6) cos(3/2).
Let f(x) = cos(x). Then,
f'(x) = -sinx
and
f"(x) = -cosx
Let a 3x/2. Then
=
f'(31/2) = -sin(3pi/2)
and
f" (3/2) = -cos(3pi/2)
Q(x), the quadratic approximation to cos(x) at a = 3/2 is:
Q(x) =
Use Q(x) to approximate cos(4.6).
cos(4.6) ≈
B](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F58cffe43-d701-4c21-9740-08fe8d98ee79%2Faeb7b35b-0559-45bd-9860-f1929877e91d%2Frcccvh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1 point) Approximate cos(4.6) using a quadratic approximation:
First note that cos(4.6) cos(3/2).
Let f(x) = cos(x). Then,
f'(x) = -sinx
and
f"(x) = -cosx
Let a 3x/2. Then
=
f'(31/2) = -sin(3pi/2)
and
f" (3/2) = -cos(3pi/2)
Q(x), the quadratic approximation to cos(x) at a = 3/2 is:
Q(x) =
Use Q(x) to approximate cos(4.6).
cos(4.6) ≈
B
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