Let's continue with these two genes that control the color and texture of tomatoes. Allele "R" generates a red coloration, and is dominant. Allele "r" generates a green coloration and is recessive. Allele "S" generates a smooth texture, and is dominant. Allele "s" generates a rough texture and is recessive. You now decide to cross your dihybrid RrSs but this one with a tomato with Rrss. RrSs x Rrss What is the probability of getting Red tomatoes with Rough texture in this new cross? Assume complete dominance and 100% penetrance and expressivity. O O O O 1/8 3/16 9/16 3/8 1/16 1/4 1/2
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- 6 5 0/1 point Let's continue with these two genes that control the color and texture of tomatoes. Allele "R" generates a red coloration, and is dominant. Allele "r" generates a green col Allele "S" generates a smooth texture, and is dominant. Allele "s" generates a rough te You now decide to cross your dihybrid RrSs but this one with a tomato with Rrss. RrSs x Rrss What is the probability of getting Red tomatoes with Rough texture in this new cro Assume complete dominance and 100% penetrance and expressivity. O 1/8 3/16 O9/16 3/8 O 1/16 X x 1/4 1/2 1/1 point Later on, you made a completely new cross. But you cannot remember the ge You are sure that one parent was (Ww). You remember your Bio class back in VCU and decided to check the ratios in If this cross (Ww X ??) produced 140 plants, and 105 have purple flowers anPurple flowers are dominant to white flowers. Identify the phenotypefor the following genotype Ff, FF, ff and determine if the genotype is heterozygous or homozygous. * For each row, you should select two columns. Purple flowers White flowers Heterozygous Homozygous Ff FF ff Brown eyes are dominant to blue eyes. Identify the phenotype for the following genotype BB, Bb, bb and determine if the genotype is heterozygous or homozygous. * 口 ロ口The white Leghorn breed of chickens is homozygous for the dominant allele C, which produces colored feathers. However, this breed is also homozygous for the dominant allele I of an independently assorting gene that inhibits coloration of the feathers. Consequently, Leghorn chickens have white feathers. The white Wyandotte breed of chickens has neither the allele for color nor the inhibitor of color; it is therefore genotypically cc ii. What are the F2 phenotypes and proportions expected from intercrossing the progeny of a white Leghorn hen and a white Wyandotte rooster?
- In Drosophila, an allele causing vestigial wings is 12.5 mu away from another gene that causes purple eyes. A third gene that affects body colour has an allele that causes black body colour. This third gene is 18.5 m.u. away from the vestigial wings gene and 6 m.u. away from the gene causing purple eyes. The alleles causing vestigial wings, purple eyes and black body are all recessive. The dominant (wildtype traits) are long wings, red eyes, and grey body. A researcher crossed wild-type flies to flies with vestigial wings, purple eyes and black body. All F1 flies were wildtype. F1 females were crossed to males with vestigial wings, purple eyes and black body. If 1,000 offspring were observed, what are the expected numbers of the following types of flies: Long wings, red eyes, grey body Long wings, purple eyes, grey body Long wings, red eyes, black body Long wings, purple eyes, black body Short wings, red eyes, grey body Short wings, red eyes, black body Short wings, purple eyes, grey…In pigs, the dominant C allele produces a curly tail. c/c homozygotes have straight tails. The recessive w allele produces white hair, whereas the W allele produces brown hair. The C and W genes (loci) are on the same chromosome. A C W / c w heterozygote (curly, brown) is test crossed to a c w / c w (straight, white) homozygote multiple times. They produce a total of 100 progeny, of which 20 have curly tails and white hair. What is the distance between the C and W loci, in map units? A.10 B. 20 C. 30 D.40In a certain plant, leaf size is determined by fourgenes whose alleles assort independently and actadditively. Thus, alleles A, B, C, and D each add4 cm to leaf length and alleles A′, B′, C′, andD′ each add 2 cm to leaf length. Therefore,an AA BB CC DD plant has leaves 32 cm longand an A′A′ B′B′ C′C′ D′D′ plant has leaves16 cm long.a. If true-breeding plants with leaves 32 cm longare crossed to true-breeding plants with leaves16 cm long, the F1 will have leaves 24 cm longand the genotype AA′ BB′ CC′ DD′. Listall possible leaf lengths and their expectedfrequencies in the F2 generation produced fromthese F1 plants.
- In chickens, comb shape is determined by genes at two loci (Gene 1 has alleles R, r and Gene 2 has alleles P, p). A walnut comb is produced when at least one dominant gene R is present at one locus and at least one dominant gene P is present at a second locus (genotype R_P). The genotype R_pp gives a rose comb phenotype; rrP_gives a pea comb phenotype; and rrpp gives a single comb phenotype. Based on this information give specific genotypes for comb shape of the parents in the crosses listed below: A) Walnut crossed with single produces 1 walnut, 1 rose, 1 pea and 1 single offspring. B) Rose crossed with pea produces 20 walnut offspring. C) Pea crossed with single produces 1 single offspring.White fruit color in summer squash is dependent on a dominant gene (W) and colored fruit to the recessive gene (w). In the presence of ww a dominant gene D produces yellow color, but when D is not present, the color is green. Upload your solution in the google classroom. Give the: F1_phenotypes_expected_from_crossing_white_fruited_WWDD_with_green_fruited_wwdd_plant F2_phenotypes_expected_from_crossing_the_F1 F2_phenotypic_ratio_expected_from_crossing_the_F1 F2_genotypic_ratio_expected_from_crossing_the_F1 Type_of_epistatis Write all phenotypes in CAPITAL letters SEPARATED BY COMMA. Write all ratio in numerical values without spacesCertainly, not all Muppets look like the one shown in the picture below, nor do they all look the same. In fact, there’s a great deal of phenotypic variation in Muppets. Two traits that have been particularly well-studied are curly hair presences and skin color. One individual is a male, and he possesses a green skin and no hair, whereas the female individual possess a curly hair and pink skin. Let’s call the gene controlling skin coloration S and that controlling hair H. In this species, both hair and green skin are recessive traits. Both of the individuals shown are homozygous. 1. What is the genotypes of Miss Piggy: 2. Kermit's Genotype: 3. If these two lovebirds (er, love-muppets?) mated, what would their offspring look like? Describe all phenotype combinations possible and the ratios in which they would occur?
- As seen in the photo, Labradors come in three colors-- black, brown and yellow. What is the genetic basis for these different coat colors? One gene produces melanin, a pigment which is deposited in the dog's fur and makes the color dark. With this gene, allele B (black) is dominant to allele b. Only in the case of a recessive homozygote (bb) will the dog's phenotype be brown. The regulatory gene is separate from the melanin gene but it acts as a switch, either turning the melanin gene on or turning it off. Allele E is dominant and allows for the melanin to be deposited in the dog's fur ("on" switch), but if the switch gene is a recessive homozygote, the melanin is blocked ("off" switch) and a yellow dog is the result! 1. Two other Labradors mate and produce puppies. Their genotypes are Bbee and BbEe. What color are each parent and what are the phenotypic rations of their offspring in the F1 Generation? Show your work with a Punnett square.. In the tiny model plant Arabidopsis, the recessive allele hyg confers seed resistance to the drug hygromycin, and her, a recessive allele of a different gene, confers seed resistance to herbicide. A plant that was homozygous hyg/hyg ⋅ her/her was crossed with wild type, and the F1 was selfed. Seeds resulting from the F1 self were placed on petri dishes containing hygromycin and herbicide.a. If the two genes are unlinked, what percentage of seeds are expected to grow?b. In fact, 13 percent of the seeds grew. Does this percentage support the hypothesis of no linkage? Explain. If not, calculate the number of map units between the loci.c. Under your hypothesis, if the F1 is testcrossed, what proportion of seeds will grow on the medium containing hygromycin and herbicide?As seen in the photo, Labradors come in three colors-- black, brown and yellow. What is the genetic basis for these different coat colors? One gene produces melanin, a pigment which is deposited in the dog's fur and makes the color dark. With this gene, allele B (black) is dominant to allele b. Only in the case of a recessive homozygote (bb) will the dog's phenotype be brown. The regulatory gene is separate from the melanin gene but it acts as a switch, either turning the melanin gene on or turning it off. Allele E is dominant and allows for the melanin to be deposited in the dog's fur ("on" switch), but if the switch gene is a recessive homozygote, the melanin is blocked ("off" switch) and a yellow dog is the result! Review the information on Labrador retrievers above. What are the phenotypic ratios of the F1 generation offspring of two dihybrids? Make sure to match the numbers with coat colors (e.g, which number in the ration goes with which color). Use a Punnett square to…