SN = 11 Investigate the adequacy of the below equal angle shape using LRFD and ASD. Use case 2 for shear lag factor.Equal Angle Dimension:AngleLength =Angle thickness=Bolt Diameter:OOO0OOOOSHERLERboltalam =Material Grade:F₁ =F₁ =Bolt Holes spacing:s1=s2 =g1=g2=g3=g4=180.00 +0.4 SN (mm)10.00 +0.1SN (mm)Tensile Loadings:DL=LL=16.00 +0.1 SN (mm)248.00 +1* SN400.00 +1* SN(Mpa)(Mpa)25.00 +0.1 SN(mm)30.00 +0.1SN (mm)25.00 +0.1*SN (mm)35.00 +0.1 SN (mm)30.00 +0.1 SN (mm)40.00 +0.1SN(mm)350.00 +1* SN300.00+1 SN(KN)(KN)

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Investigate the adequacy of the below equal angle shape using LRFD and ASD. Use case 2 for shear lag factor. Equal Angle Dimension: Anglength= 180.00 +0.4 SN (mm) Angleikness 10.00 +0.1 SN (mm) O O O O O O O O O Hallar Bolt Diameter: boltsam Material Grade: Bolt Holes spacing: s1= $2= g1= g2= g3- 84- Tensile Loadings: DL= LL= 16.00 +0.1 SN (mm) 248.00 +1.SN 400.00 +1.SN (Mpa) (Mpa) 25.00 +0.1 SN (mm) 30.00 +0.1 SN (mm) 25.00 +0.1 SN (mm) 35.00 +0.1 SN (mm) 30.00 +0.1 SN (mm) 40.00 +0.1 SN (mm) 350.00 +1.SN 300.00+1 SN (KN) (KN)

Investigate the adequacy of the below equal angle shape using LRFD and ASD. Use case 2 for shear lag factor. Equal Angle Dimension: Anglength= 180.00 +0.4 SN (mm) Angleikness 10.00 +0.1 SN (mm) O O O O O O O O O Hallar Bolt Diameter: boltsam Material Grade: Bolt Holes spacing: s1= $2= g1= g2= g3- 84- Tensile Loadings: DL= LL= 16.00 +0.1 SN (mm) 248.00 +1.SN 400.00 +1.SN (Mpa) (Mpa) 25.00 +0.1 SN (mm) 30.00 +0.1 SN (mm) 25.00 +0.1 SN (mm) 35.00 +0.1 SN (mm) 30.00 +0.1 SN (mm) 40.00 +0.1 SN (mm) 350.00 +1.SN 300.00+1 SN (KN) (KN)

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter5: Beams

Section: Chapter Questions

Problem 5.6.3P

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