In the circuit shown in Figure determine the current Ix using source transformation method 10 V 20002 3092 ww www 5002 ww 10 mA 800 6002 € 1002 ww 1092 3672-2024/04
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- %3D ) Drurde (l0o1102 and (oWhat is the difference between the cut-off voltage VGS0 f and the narrowing voltage Vp? Explain this with the diagramIn the figure: R1 = 27.3 Q, R2 = 93.1 Q and R3 = 1571.12 Q, then determine the value of the source current Is. 12 13 RT R1 R2 R3 E 1.33 0.98 1.44 1.73 1.15
- Pleasea) Voltage at Node "A" in V is b) Current flowing through R5 in mA is c) Current flowing through R6 in mA is d) Current flowing through R7 in mA is e) Power dissipated by R8 in micro W is25bCAq36iTACoM7x7Q/formResponse abs together, right-click a tab Got it Remind me later none of the mentioned O * Q7: For the circuit shown, find R and the power in 10 Ohm resistance 15 10 15 R 41.5 A 20 V R= 8 Ohm P= 22.5 mw O none of the mentioned R= 6 Ohm P= 2.25 w O R= 6 Ohm P= 22.5 w O R= 15 Ohm P= 22.5 w B.
- Count me in! DIRECTIONS. Study the diagram showing the placement of electronic components. Based on the letter or schematic symbol, list down in the table below all the electronic components you can identify. 02E OUTPUT TO R6 RS 12V Q2 R10 D8 Q2 R3 R4TR1 R2 D4 Cs 03 06 D3 D2 TO NEGATIVE OUTPUT (GND OUTPUT) Component Number 1. 2. 3. 4. ASZQ2/ find the l1 ,İz and İr2 for the figure below R in 1 E, SV E 10 VR1= R2- 330ohms 82ohms Vsurd R- mA ma Vmes/imes mA Vmes/imes mA ohms ohms 2 0.0060 0.00604 331.13 0.0244 0.02393 83.58 4 0.0121 0.01213 329.76 0.0488 0.04779 83.69 6 0.0181 0.01834 327.15 0.0732 0.07183 83.53 80 0.0242 0.02451 326.39 0.0976 0.09437 84.77 Why? 2. Does 'a three digit color coding of resistor values' limit producible resistor value ranges? Why? If you need to increase these range what would be your solution? 3. Write down at least three reasons which cause difference between R1 (R2) and R = Vmes/imes values in the below table?
- Estimate voltage E2 when E1=90sin2400t V, R1=R2=20 ohms, L1= L2=3mH and M=0.15mHQuestion 2 Figure Q2 shows the exact equivalent circuit of a 50 Hz, 30 kVA, 2200 V/250 V single- phase transformer. Given that Rp = 0.9 №, Xp = 2 N, Rc = 10 MN, Xm 13 ΜΩ, Rς = 0.0094 , Xs 0.038 N and iron losses at the rated voltage is 10 kW. A load with 0.8 lagging is connected to the secondary circuit of the transformer. ܫܫܫܫ (b) - (a) Draw the approximate equivalent circuit referred to primary and calculate the equivalent winding resistance and reactance referred to primary. Based on the circuit parameters calculated in part (a), determine the full load efficiency.Use Kirchhoff's Law to solve for the current passing through each resistor. Compare it with what you got from the PHET Simulation A D 392 www 6V E www F 192 www 292 352 www 9V B C