Given the following NDFSM M, the correct statements are: 90 b 91 94 a a q2 95 93 L(M)= {w€ (a, b)*: w contains aaa or bab or |w| is even). L(M) = {w € (a, b)*: w contains aaa or bab or w| is odd}. OL(M) = {w€ {a, b}": The 2nd to the last character of w is a or |w| is even). OL(M) = {w € (a, b)*: The 2nd to the last character of w is a or |w| is odd).

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Given the following NDFSM M, the correct statements are:
q0
8
b
a
q1
94
a
b
a
a
q2
q5
a
93
L(M) = {w € {a, b}*: w contains aaa or bab or w| is even).
OL(M) = {w € {a, b}*: w contains aaa or bab or w| is odd}.
L(M) = {w € {a,b}*: The 2nd to the last character of w is a or|w| is even}.
L(M) = {w = {a, b}*: The 2nd to the last character of w is a or |w| is odd}.
Transcribed Image Text:Given the following NDFSM M, the correct statements are: q0 8 b a q1 94 a b a a q2 q5 a 93 L(M) = {w € {a, b}*: w contains aaa or bab or w| is even). OL(M) = {w € {a, b}*: w contains aaa or bab or w| is odd}. L(M) = {w € {a,b}*: The 2nd to the last character of w is a or|w| is even}. L(M) = {w = {a, b}*: The 2nd to the last character of w is a or |w| is odd}.
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