From the following data, find the % (w/w) cream of tartar (KHC4H406, MM=188): Wt of sample = 1.4160 g NaOH titrant used 20.87 mL %3D HCI used for back titration = 1.27 mL 1.00 mL HCI 1.12 mL NaOH 1.00 mL HCI 0.01930 g CaCO3 89.08% (w/w) O 87.12% (W/w) 47.75% (w/w) O 95.59% (W/w)

Curren'S Math For Meds: Dosages & Sol
11th Edition
ISBN:9781305143531
Author:CURREN
Publisher:CURREN
Chapter14: Formula Method
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From the following data, find the % (w/w) cream of tartar (KHC4H406, MM=188):
Wt of sample = 1.4160 g
NaOH titrant used = 20.87 mL
HCI used for back titration = 1.27 mL
1.00 mL HCI 1.12 mL NaOH
1.00 mL HCI A 0.01930 g CaCO3
89.08% (w/w)
87.12% (w/w)
O 47.75% (w/w)
O 95.59% (W/w)
Transcribed Image Text:From the following data, find the % (w/w) cream of tartar (KHC4H406, MM=188): Wt of sample = 1.4160 g NaOH titrant used = 20.87 mL HCI used for back titration = 1.27 mL 1.00 mL HCI 1.12 mL NaOH 1.00 mL HCI A 0.01930 g CaCO3 89.08% (w/w) 87.12% (w/w) O 47.75% (w/w) O 95.59% (W/w)
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