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- Draw a seven-segment display, show the number highlighted in figure 1 (d3 -d0 are the input, a -g are the outputs). III. Simulation Wavetorm Editor - Cers/Ahmad Fainuz/Desanop/DLD Lab Practice/bedseg - beaeg - bcaseg 2018o03121936sim.vwwt Ee ep Ea w smutation search altera.com Haster Time Bar: ops Pointer: s29 us Start End iterval 529 us o ps 0 ps २ 2.56 us S12 us 75 us 10.24 us 12 s 15.36 us 172 us value at Name Ops do Figure 1For the circuit shown below, determine the voltage of the -j10 capacitive reactance. -jsa jl0n 0.5L-90 ILOA(1 -j102 jsn 52 102 AASAP
- The sum of the following two e.m.fs will be e1 = 10 sin wt and e2 = 10 cos wt O 10 O 20 sin wt O 14.14 cos wt O 14.14 sin (wt + TT/4)8PFE-5 What is the current I, in the circuit ? 6ej2t 16 -j1Q I₁₁ 0Please show your detailed solution Number 14 The current in a series inductive circuit is 7.5 A at 25 Hz. The circuit takes 425 W, and the power factor is 0.47. The resistance of the circuit is A. 7.32 ohms C. 7.98 ohms B. 7.86 ohms D. 7.56 ohms
- A certain impedance is given by 1012° N. Does the current lead or lag the voltage, and by how many degrees? Fill in the blanks. The current the voltage by(b) Figure Q2 shows a power system network. The generators at Bus 1 and Bus 2 are represented by their equivalent current sources with the reactance in per unit on a 100MVA base. The lines are represented by n model where the series and shunt reactances are expressed in per unit on a 100MVA base as well. However, the load located at Bus 3 and Bus 4 are expressed in MW and MVar. Reconstruct the network impedance shown in the figure into the network admittance by assuming the voltage magnitude at Bus 3 and Bus 4 are 1.0 per unit, respectively. (i) (11) Calculate the bus admittance matrix of the system.P 269 W, Q = 150 VAR (capacitive). The power in the complex form is: %3D Select one: a. 150 + j269 VÀ b. None of these c. 150- j269 VA d. 269-j150 VÀ
- "If lab is equal to 595.8252306 and lb is 344296, the phase sequence is:" O POSITIVE O NEGATIVEQl: For the circuits shown in figures. If the temperature has changed from 25°C to 65°C, find Alc. le=1.5mA at 25°C, R =250k2, R=1k and Re-0.5k2. 25°C 65°C B55 70 Ico Rf Re InA 16nA VBE 0.6 0.5 ReFor this question i get all the way to the point where i have a + bj [ 0.0166 + 0.1502j ] however, calculating the phase of this specific question just does not match up with the answer provided by my university. the formula that i am using is that the phase = 90-arctan(Imaginary/Real) which in this particular problem should add output a phase of -96,31 degrees. However it does only output 6,31 and the input voltage does not contain -90 so i dont get it.