Below shows the following hexidecimal values: Address 1000: 13 Address 1001: 03 Address 1002: C5 Address 1003: 00 Provide the format and assembly language instruction for the following hexadecimal values
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Below shows the following hexidecimal values:
Address 1000: 13
Address 1001: 03
Address 1002: C5
Address 1003: 00
Provide the format and assembly language instruction for the following hexadecimal values.
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- Computer Science Write an assembly language program for the 8085 Microprocessor to find the smallest of the given three numbers.Input: 2230H: 3AH2231H: A3H2232H: 18HStore the result in memory location 2250H.Note: Starting Address of the Program (Mnemonic) Code: 2200HMicro processor 8086 Assume that there are two bit 32-bit numbers:4444DDDDH and CCCC0003H .write an assembly program program to sum them , if it’s possible to do it with intel 8086 microprocessor then cross check (4444DDDH and CCCC0003H0001 = Load AC from memory 0010 = Store AC to memory 0101 = Add to AC from memory 0011 = Load AC (the accumulator register) from an I/O device 0111 = Store AC to an I/O device With these instructions, a particular I/O device is identified by replacing the 12-bit address portion with a 12-bit device number. Remember that a number ending with a small ‘h’ means the number is a hexadecimal number. What is the hexadecimal string that expresses the following instructions? Load AC from memory location 62h. Add the contents of memory location 451h to AC. Store AC to memory location 8h. Store AC to I/O device number 8h.
- Indirect Addressing Mode Instruction 002A J@ RETADR 3E20030030 RETADR RESW 1 1.Instruction Starts with 002A2.Opcode of J is 3C3.Object code is 3E2003Please show the detailsImplement the following arithmetic expression in assembly language: EAX = –val2 + 7 –val3 + val1. Assume that val1, val2, and val3 are 32-bit integer variablesSuppose r0 = ox300010A0, r2 = 0x00000011, and the memory layout is as follows Address: Data: 0x300010A7 0x72 0x300010A6 0XA5 0x300010A5 0x9F 0x300010A4 0x00 0x300010A3 0x50 0x300010A2 0x2B 0x300010A1 0XA5 0x300010A0 0x01 -What is the Value of r0 and r1 after executing LDR r1, [r0, #2] -What are the values of r0 and r1 after executing the following code? Illustrate your process in a memory map. LDR r1, [r0], #3 ADD r1, r1, r2 STR r1, [r0, r#4]
- The ALU unit of a microprocessor manipulate logically or arithmetically on array of Bits. Below are two set of Bits equations placed in the ALU sequentially: Calculate 11100011 AND 11001110 and Calculate 01010111 OR 11001100 By your reasoning and application of principle of ALU solve this equations step by stepSuppose r0 = ox300010A0, r2 = 0x00000011, and the memory layout is as follows Address: Data: 0x300010A7 0x72 0x300010A6 0XA5 0x300010A5 0x9F 0x300010A4 0x00 0x300010A3 0x50 0x300010A2 0x2B 0x300010A1 0XA5 0x300010A0 0x01 -What are the values of r0 and r1 after executing the following code? Illustrate your process in a memory map. LDR r1, [r0], #3 ADD r1, r1, r2 STR r1, [r0, r#4]Bus d'adresse Ox0 A7 0 A6 0 AS Oxo 0 A4 0 A3 0 A2 0 A1 Lecture Bus de contrôle Écriture AO Bus de données Mémoire d'Instructions Adr Adr Ctr Ctr Ctr Ox Mémoire de données Clavier Écran CD 0 EN Data Data EN Data EN Data EN Write the instruction STR R2, [R3] in hexadecimal (using 2 bytes). АО A1 DO D1 D d u r D3 D2 09
- Part A For each byte sequence listed, determine the Y86 instruction sequence it encodes. If there is some invalid byte in the sequence, show the instruction sequence up to that point and indicate where the invalid value occurs. For each sequence, the starting address, then a colon, and then the byte sequence are shown. 0x100: 30f3fcfffff40630008000000000000 0x100: 30f3fcfffffff irmovq $-4,%rbx Ox10a: 40630008000000000000 | rrmovq %rsi,0×80A(%rcx) O0x115: 00 halt Ox100: 30f3fcffffffff irmovq $-4,%rbx Ox10a: 40630008000000000000 | rmmovq %rsi,0x800(%rbx) Ox114: 00 halt 0x100: 30f3fcfffffffff rrmovq $-8,%rbx Ox109: 40630008000000000000 | rmmovq %rsi,0x800(%rbx) 0x200: a06f800c020000000000000030f30a00000000000000 0x113: 00 halt 0x100: 30f3fcffffffffff irmovq $-4,%rbx 0x200: a06f pushq %rsi 0x10a: 40630008000000000000 | rmmovq %rsi,0x800(%rbx) Ox202: 800c02000000000000 call proc Ox116: 00 halt 0x20b: 00 halt 0x20c: proc: Submit Request Answer 0x20c: 30f30a00000000000000 | irmovq $10,%rbx…80x86 Intel Assembly language Write an assembly language to declare all the variables needed in the following instructions and initialize them with a value of your choice. Then write assembly language code to perform the following C instruction. int number1; int number2; int number3; int number4; number1 = -number2 + (number3 - number4) if (number1 > number3) number1 = number2; else number1 = number3;E In the following code block(Reference:Q11), you will a set of assembly instructions with corresponding line numbers (line numbers are for informational purpose only and they are not part of the source code). 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 mov edx, 5 dec ecx jmp LABEL1 mov eax, 1 LABEL1: mul edx jmp ecx mov edx, 0678h sub edx, eax jmp DWORD PTR [edx] neg ebx add ecx, ebx mov eax, 0 For each of the conditions/scenario listed below, indicate the corresponding line number (that cause or is associated with the condition/scenario). Enter 0 (Zero) if the condition is not caused by the block of code. 1) Memory indirect jump: type your answer... type your answer... type your answer... type your answer... 2) Register indirect jump: 3) Relative short jump: type your answer... 5) Two's complement type your answer... 4) Relative near jump: 6) Unreachable code