According to Lacey's theory of channel design, what will be the velocity of flow in the channel corresponding to a discharge of 140 cumec and silt factor 1,0?
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- What are the values of coefficients a and c if velocity distribution in a laminar boundary layer on a flat is: y where, n == A B C ƒ (n)= = =a+bn+cn² + dn³ U. D 2 and 1 0 and 1 1 2 and 0 O and OThe data in the table below is for a closed-polygon traverse. Course Azimuth Length (m) AB 75°14'47" 519.674 BC 455.265 CD DE EA Interior Angles A = 12°25'31" B 48°19'25" 433.426 C = 126°37'24" 425.558 D = 46°03'36" 109.434 E = 306° 34'19" Part A Compute the preliminary azimuths. O AZAB = 57°14'47". Azpc = 303°34′09", AzcD=250°11'30". AZDE=116°15'03". AZEA = 242° 49'19" O AZAB = 75°00'47", AZ BC = 303°00'09", AzcD = 250°00'30", AZDE = 116°00'03", AZEA = 242°00'19" O AZAB = 75°14'47". AzBc = 313° 34'09", AzcD = 25°11'30", AZDE = 116°10'00", AZEA = 224° 49'19" O AZAB = 75°14'47". AzBC = 303°34'09", AzcD = 250°11'30". AZDE = 116°15'03". AZEA = 242° 49'19" Part B Compute the unadjusted departures. Express your answers in meters to six significant figures and separated by commas. AB, BC, CD, DE, EA= Part C vec IVE ΑΣΦΠ ← A Compute the unadjusted latitudes. Express your answers in meters to six significant figures and separated by commas. AB, BC, CD, DE, EA= ΠΑΠΑΣΦ Π vec ^ A ? ? m, m, in mi,…If the grid spacing of a finite difference 2D groundwater model with a regular grid (Ay = Ax) is halved how wound that affect the truncation error: O a. No effect as the truncation error is not real. b. It would reduce the truncation error by a factor of four. O c. It would halve the truncation error. O d. It would increase the truncation error by a factor of four. Clear my choice
- 5. Circle as many errors as you can in the flownet shown. Medium sand Silty sand Impervious concrete wall Impervious clay ▼ Impervious rock Figure 8.14 Trial flow net for Problem 8.2. Note: This flow net is not drawn correctly, and should not be used as an example!Please explain how to calculate the number of flow channels (Nf) and number of equipotential drops (Nd). The more detail the better. I don't need the problem solved, just Nf and NdQuestion:A rectangular channel is 3m wide and has a depth of flow of 1.5m. The channel roughness can be assumed to be 0.015 and the bed slope is 0.001. Calculate1. The height by which the bed should be raised to just produce critical depth2. The width by which the bed should be narrowed to just produce critical depth Note : Explain with diagram and sir you have commited a mistahe in calculating the ctitical depth for rectangular channel which is actually yc = (q2/g)1/3
- H.W 2 Find the bed width and bed slope of a canal having the following data. Discharge of the canal = 40 cumec Permissible mean velocity = 0.95 m/sec. Coefficient of rugosity, n = 0.0225 Side slope = 1:1 B/D ratio = 6.5 %3DH.W2 o HW (2)for fig.below find the average depth of p.p.t use theissen polygon method and r = 6km ? S4€ 108.45 mm 81 81.76 mm 88.5 mm S5 83 76.2 mm S2 95.2 mm R = 6 KmA wide, clean-earth river has a flow rate q = 150 ft3/(s . ft).What is the critical depth? If the actual depth is 12 ft, whatis the Froude number of the river? Compute the criticalslope by (a) Manning’s formula and (b) the Moody chart.
- Q=25m^3/s b= 4m Yu=6m Fgd=500knQ3/ A Trapezoidal open channel. The following data are available:- 1- Cross -sectional area of flow in the channel A = 75 (m). 2- Wetted perimeter of the channel P = 100 (m). 3- Longitudinal slope of bed level of the channel S, = 0.0001 4- Bed width of the channel B = 10 (m). %3D 5- Width of channel at water level W = 2B (1/3) 6- n = 0.025 {S/mu/3)} Find:- 1- Flow rate in the channel Q. 2- Side Slope of the channel Z. 3- Fluids Number Fr. 4- Type of flow in the channel.SITUATION: Water flows through an almost level rectangular channel 3 m wide at 12 m^3/sec. The depth of the channel gradually increases from 1.0 to 1.1 m for length of 5 m. Obtain the value of the roughness coefficient. 0.016 0.015 0.014 0.012