A student is looking to react barium ions in solution (Ba²+ (aq)) with something that will make them precipitate. According to the provided table, she could add Lithium Oxide accomplish this. Let's say she added 0.750 g of her chosen compound to a solution containing 1.250 g of Ba2+. If her chosen compound was the limiting reactant, she would be able to produce [Select] grams of precipitate. If Ba2+ was the limiting reactant, she would be able to produce [Select] reactant was [Select] = percent yield for the reaction was [Select] to grams of precipitate. This means the limiting = . If she actually isolated 1.002 g of precipitate, then her %.

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A student is looking to react barium ions in solution (Ba2+ (aq)) with something that will make them
precipitate. According to the provided table, she could add Lithium Oxide
accomplish this.
Let's say she added 0.750 g of her chosen compound to a solution containing 1.250 g of Ba²+. If her
chosen compound was the limiting reactant, she would be able to produce
[Select]
+ grams of precipitate. If Ba2+ was the limiting reactant, she would be
A grams of precipitate. This means the limiting
able to produce [Select]
reactant was [Select]
to
H
.If she actually isolated 1.002 g of precipitate, then her
percent yield for the reaction was [Select]
%.
Transcribed Image Text:A student is looking to react barium ions in solution (Ba2+ (aq)) with something that will make them precipitate. According to the provided table, she could add Lithium Oxide accomplish this. Let's say she added 0.750 g of her chosen compound to a solution containing 1.250 g of Ba²+. If her chosen compound was the limiting reactant, she would be able to produce [Select] + grams of precipitate. If Ba2+ was the limiting reactant, she would be A grams of precipitate. This means the limiting able to produce [Select] reactant was [Select] to H .If she actually isolated 1.002 g of precipitate, then her percent yield for the reaction was [Select] %.
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