1 1 Load parallel data 6.7 Draw the logic diagram of a four-bit register with four D flip- flops and four 4×1 multiplexers with mode selection inputs s1 and so. The register operates according to the following function table. (HDL ―see Problem 6.35(e), (f)) s1 s0 Register Operation 0 0 No change 10 Complement the four outputs 01 Clear register to 0 (synchronous with the clock)
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- d) Draw the schematics of 4-bit synchronous and asynchronous MOD-8 counters and comment on their pros and cons. e) Calculate the noise margin for a logic gate with the following logic levels: VIL = 1.1 V, VIH = 3.2 V, VOL = 0.6 V, VOH = 4.0 V.6. i) For the circuit shown in Figure Q16, Find the logic functions of X and Y Figure Q1 ii) Simplify X and Y using Boolean algebra. hp ort deleteparity generator design, construct and test a circuit that generates an even parity bit ffrom four messages bits . use XOR gates. adding one more XOR gate, expand the circuit so that it generates an odd parity bit also.
- The numbers from 0-9 and a no characters is the Basic 1 digit seven segment display * .can show False True In a (CA) method of 7 segments, the anodes of all the LED segments are * "connected to the logic "O False True Some times may run out of pins on your Arduino board and need to not extend it * .with shift registers True FalseDesign the interfacing circuit shown below and write a program to display single digit (between 0 and 9) prime numbers followed by even numbers, the next odd numbers and repeats in 7-segment displays and its equivalent 8-bit binary value in LEDS. a) When displaying Prime numbers, the first 7-segment display must show "P" and the second 7-segment display must show prime numbers one by one b) When displaying Even numbers, the first 7-segment display must show "E" and the second 7-segment display must show even numbers one by one c) When displaying Odd numbers, the first 7-segment display must show "O" and the second 7-segment display must show even numbers one by one- The stack memory is addressed by a combination of the plus offset. The PUSH and POP instructions always transfer between segment -bit number the stack and a register or memory location in the 8086 microprocessors. For string instructions, DI always addresses data in the segment. The 8086 LOOP instruction decrements register for a 0 to decide if a jump occurs and tests it
- Q4(a) Adder is divided into three types which are half adder, full adder, and parallel adder. Illustrate the implementation of full adder using half adder with necessary logic gates. (i) (ii) Figure Q4(a)(ii) shows the input timing diagram for a full adder. Illustrate the timing diagrams for output S and Cout- Cin Cout Figure Q4(a)(ii)Q4(a) Adder is divided into three types which are half adder, full adder, and parallel adder. Illustrate the implementation of full adder using half adder with necessary logic gates. (i) (ii) Figure Q4(a)(ii) shows the input timing diagram for a full adder. Illustrate the timing diagrams for output S and Cout- B Cin Cout Figure Q4(a)(ii) (iii) Given A = 111001 and B = 100010. Construct a 6-bit parallel adder to solve for A + B.Problem Statement: You design a circuit of a decade counter that will count from 0-9 only. You will only be using the following: (a) Button – only 1 button will be used to trigger the counting. (b) Flip flop IC to used as counting circuit with 4 - BITS binary OUTPUT. (c) IC's for Decoding the Binary OUTPUT of Flip-flops to Decimal Output (d) 7- Segment Display to display the OUTPUT from 0-9. Block Diagram: 4 Bit Binary Flip-Flop 7-Segment Display Button Decoder Circuits Circuits
- Electrical Engineering Draw 2, 1 bit ALUS to create a basic 2 bit ALU. the carry out and carry in bits must ripple across. The ALU should subtract/add, logical NOR, logical AND, and logical OR. Draw out the adding logic circuit6) Write an 8086 assembly language program to multiply the contents of the registers CL & BL by using repeated addition and store the result in AX. 0006Q3) A - Convert the Excess-3 to binary number : ( 110001011100.10001010)ex-3 B- convert each Gray code to binary: 1-( 011010001001)G 2-(59)D