6. The equation below shows the combustion of butane (C4H10). How many moles of water can be produced by 12.5 moles of C4H10 reacting with excess oxygen? 2C4H10 + 1302 --> 8CO2 + 10H2O (Hint: 1 step conversion) * O 2.50 moles O 62.5 moles ) 125 moles O 202 moles

6. The equation below shows the combustion of butane (C4H10). How many moles of water can be produced by 12.5 moles of C4H10 reacting with excess oxygen? 2C4H10 + 1302 --> 8CO2 + 10H2O (Hint: 1 step conversion) * O 2.50 moles O 62.5 moles ) 125 moles O 202 moles

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter4: Stoichiometry

Section: Chapter Questions

Problem 4.87PAE

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

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6. The equation below shows the combustion of butane (C4H10). How many
moles of water can be produced by 12.5 moles of C4H10 reacting with excess
oxygen? 2C4H10 + 1302 --> 8CO2 + 10H2O (Hint: 1 step conversion) *
ーーン
O 2.50 moles
O 62.5 moles
) 125 moles
) 202 moles

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