5. Select the lightest W12 shape for a column subjected to an axial compressive load of 730,000 Ibs. The unbraced length of the column is 22 feet and uses fixed connections. Use the AISC column tables.
Q: A 470 mm-diameter, non-slender, spiral column is symmetrically reinforced with 8-16 mm vertical…
A: Appreciate if there is detailed work with explanation and finds you helpful for ease of…
Q: If the Engineer use 7pcs -25mm bar having fy = 345 Mpa and concrete strength f'c = 21 Mpa for the…
A: Given values, Steel bars: n=7 nos, d= 25 mm dia, fy = 345 MPa, Concrete : fck = 21 MPa Concrete…
Q: If the Engineer use 7pcs -25mm bar having fy = 345 Mpa and concrete strength f'c = 21 Mpa for the…
A: Ultimate axial capacity of a column : PU = 0.4fck Ac + 0.67fy Asc where, fck = 21MPa fy = 345MPa…
Q: A beam section shown below will be subjected to a maximum service dead load of 215 KN.m. Determine…
A: Given: D.L = 2.15KN/M f'c = 21 Mpa fy = 415 Mpa 5bars of 25mm Size = 360*650mm 1.Calculation of Area…
Q: An axially loaded square tied column is to be designed for the following service loads. DL = 2000 kN…
A:
Q: Determine the allowable ultimate axial load on a rectangular short tied column 12 by 18 in. (300 by…
A: Solution:
Q: A 480-mm-diameter, non-slender, spiral column is symmetrically reinforced with 10-20 mm vertical…
A:
Q: A steel pipe column (standard pipe weight) to support a load of 40 k and a length of 20 feet. Fy 36…
A: Given data: Fy= 36 ksiLoad on column = P = 40 K⇒Fy=PAor, A=PFy=40 k36 ksi=1.11 in2…
Q: Find the capacity (allowable load) of a W14 x 61 pin-ended column with an unbraced length of 10ft.…
A:
Q: Design a square tied column to support an axial dead load D.L of (357) k and an axial live load L.L…
A: To design square tied column
Q: 1. A vertical column with pinned ends is subjected to an end load P. The column has a radius of…
A: Given:- Both the ends of the columns are pinned The radius of gyration of the column = r = 150 mm…
Q: Determine the factored axial load for the short, spirally reinforced circular column according to…
A: Solution-f'c = 27.6 Mpa fy = 420 Mpa b = 350 mm h = 650 mm (assume)To Determine The factored…
Q: A 480-mm-diameter, non-slender, spiral column is symmetrically reinforced with 10-20 mm vertical…
A: Steel reinforcement = 10 bars of 20 mm diameter axial live load = 977 kN f'c = 24 MPa fy = 280 Mpa
Q: Q1: Determine the max service live load that the column shown can support if the live load is twice…
A: Given, The dead load,(Lc )x = KxLx = 18 ft (Lc )y = KyLy = 12 ft Fy = 50 ksi Properties of section…
Q: Design a square R.C. column to resist an axial load of 400 kN due to dead load and 240 kN due to…
A: Given data, Dead load = 400 kN Live load = 240 kN Steel grade = 415 N/mm² Concrete grade = 25 N/mm²…
Q: Select the minimum-size rectangular column for the same data as in Example 2(A square tied column…
A: Solution Given Data f'c= 5 ksify= 60 ksiAxial load PD=150 kipsDead load PL=250 kipsDead load Bending…
Q: Determine the minimum plate thickness required for the built up column to safely carry a service…
A: W 14 x 68 specification:- d (depth) = 14.04" bf (width) = 10.035" width of plate = 12" (given) tw…
Q: Determine the diameter of a spiral column axially loaded with 1100 kN dead load, and 1000kN live…
A: Given data Dead load (WD) = 1100 KN Live load (WL) = 1000 KN Steel ratio = 0.02 fc' = 28 MPa fy…
Q: Determine the ultimate axial load capacity of a rectangular tied column 350 mm x 450 mm having…
A: step 1-
Q: A 480-mm-diameter, non-slender, spiral column is symmetrically reinforced with 6-16 mm vertical…
A:
Q: Determine the critical buckling load for each of the columns, using the Euler equation = 29,000 ksi.…
A:
Q: 1. Design a column base plate to support an axial load of 1000 kN. Fp = 0.25fc, Fy = 248 MPa, fc =…
A: The question is based on the column in the shape of the I section. The axial load on the column,…
Q: Determine the ultimate axial load capacity of a rectangular tied column 350 mm x 450 mm having…
A: step 1-
Q: A 400-mm diameter, non slender, spiral column is symmetrically reinforced with 10-25 mm vertical…
A: First, we will calculate the area of steel in the column. Then the total area of the column will be…
Q: Select a structural-steel wide-flange beam to carry the load shown in the figure below. S, = 22,000…
A: Sb = 22000 psi Sg = 14500 psi
Q: Design a column with an effective length of 670.56 cm to support a dead load of 289 kN, a live load…
A: Solution: Given: DL = 289 kN LL = 489 kN WL = 640 kN L = 670.56 cm = 22 ft fy = 345 MPa = 50 ksi
Q: An HSS 18 x 18 x 7/8 with F, = 50 ksi is used for an 20 ft long column with simple end supports.…
A: The properties of HSS 18 x 18 x 7/8 are r=6.92 inAg=58 in2 It is required to determine the…
Q: A 400 mm x 500 mm rectangular tied column is reinforced with eight (8) D28mm longitudinal bars, four…
A: The given section:
Q: Problem Find the capacity (allowable load) of a W14 x 61 pin-ended column with an unbraced length of…
A: Given:- The column section used is W14×61 The end condition of the column is both ends are pinned…
Q: A 410-mm-diameter, non-slender, spiral column is symmetrically reinforced with 8-20 mm vertical…
A: Calculate design strength of column
Q: Design a rectangular tied column with the long side equal to two times the length of the short side.…
A:
Q: Problem 04 Design a column with an effective length of 22 ft. to support a dead load of 65 k, a live…
A:
Q: C16. For the beam and loads given below, select the stirrup spacing assuming f,' = 3,500 psi, f, =…
A: To find stirrup spacing
Q: PROBLEMS 10.1. Determine the allowable ultimate axial load on a rectangular short tied column 12 by…
A: Given: Dimension of rectangular short tied column = 300 x 450 mm Number of reinforcement bars = 6…
Q: 1 Select the lightest available square HSS Class C (G40.21 350W) section to support the concentric…
A:
Q: QA.77. Design a square tied column to support an axial dead load of 575 kN and an axial live load of…
A: The values given in the question are as follows Axial dead load(PD)=575 kN Axial live load(PL)=710…
Q: An 11-foot long reinforced concrete cantilever beam is limited in the cross-sectional dimensions tob…
A: The superimposed dead load=Dead load UDL=1.5 k/ft live load UDL=2 k/ft The dimensions are: b=14 in…
Q: A 400-mm-diameter, non-slender, spiral column is symmetrically reinforced with 10-25 mm vertical…
A: P = 0.85 [0.85*fc (Ag - Ast) + fy * Ast] here, fc = 24MPa fy = 280MPa Ag = 3.1416/4…
Q: Example 7.29. A column, 4.5 m in height, and effectively resti directions at both the ends carries…
A: Given Data: Height of column=4.5 m and restrained in position at both ends Leff =0.67*4.5=3.015 m…
Q: - Determine the allowable ultimate axial load on a rectangular short tied column 12 by 18 in. (300…
A:
Q: Calculate the shear capacity, øV, for a 350 WC 280 column. Answer should be in kN. Do not add units…
A: Given: The column designation is 350 WC 280.
Q: Q1: Determine the max service live load that the column shown can support if the live load is twice…
A: Given , Fy=50 ksiKxLx=18 ftKyLy=12 ft
Q: Design a square tied column to support an axial dead load D.L of (330+ 60) k and an axial live load…
A: To design square tied column
Q: 10.1. Determine the allowable ultimate axial load on a rectangular short tied column 12 by 18 in.…
A: Given: Dimension of rectangular short tied column = 300 x 450 mm Number of reinforcement bars = 6…
Q: QA.7. Design a square tied column to support an axial dead load of 565 kN and an axial live load of…
A: Data Given: Axial dead load = 565 kN Axial live load = 760 kN f'c = 27.5 MPa fy = 412.6 MPa Asked:…
Q: A standard steel 14 in. Schedule 40 pipe carries, a 650 lb load at the center of a 28 in. span,…
A: Hi! Thank you for the question As per the honor code, We’ll answer the first question since the…
Q: Determine the maximum service live load that the column shown can support if the live load is twice…
A: A C 8×18.75 flange section is used for the column The cross section area of the channel is A= 5.51
Q: For a 3 m Channel C12 x 30, determine the maximum axial compressive service load that can be…
A: L = Length of channel = 3 m = 3000 mmChannel C12x30LL = 2DLBottom end is fixed while the other end…
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- 1. A steel column 10 m long is fabricated from a cover plate and C section arranged as shown. Determine the safe compressive load. Fy = 248 MPa, E= 200 GPa. Use AISC/NSCP Specs. 450 mm -cover plate 'I 12 mm y2 IP d2 10 m C 310 x 37 A = 4720 mm? d = 305 mm bf = 77 mm tf = 12.7 mm tw = 9.8 mm C 310 X 37 a) Both ends of column are fixed b) Both ends of column are hinged c) One end fixed, the other end hinged Use design values of k. tw d=305- Ix = 59.9x10° mm ly = 1.85x10° mm x = 17.1 mm x=17.1steel Design Civil Engineering Please show solutions: AW 310 x 118 section with a length of 8.0 m is used as a column. Determine the safe axial load the column can carry using AISC specifications with Fy = 345 MPa when: Properties of W 310 x 118 A = 15000 mm² rx = 136 mm ry = 77.6 mm A. column ends are fixed B. one end of the column is fixed; the other free Use LRFD Answers: A.] For Ag = 248.06X15000 100 3720,9kw $en=0.90x3720.9 = 3348.21 kW B.JPn= For Ag =40.72 x 15 000 LOW Pr= 0.90x610,81 = 549.729 KN• AW 310 x 118 section with a length of 8.0 m is used as a column. Determine the safe axial load the column can carry using AISC specifications with Fy = 345 MPa when: a) column ends are fixed b) one end of the column is fixed; the other free Properties of W 310 x 118 A = 15000 mm² rx = 136 mm ry = 77.6 mm CIVIL ENGINEERING- STEEL DESIGN
- Question 1 Check that the medium-term load of 38 kN applied to the spaced column shown in below complies with the design requirements of BS 5268-2. The column consists of two 38 x 150 C22 timbers 76 mm apart. All joints are glued and intermediate packs are 250 mm long. suitable connection #### x ->89² 6:38. Y T -end blocking AP 100 intermediate blocking L₂ 1₁ x W L W EFH 400 m 38kN medium term load -ICHICHID -200 600 600 600 600 600 600 200 38kN medium term loadA column is constructed using a circular steel tube filled with concrete. The properties are listed below. Please find: 1. The maximum allowable axial force, P 2. Shortening (in inches) of a 12 ft column with this cross-section when P is applied 3. The strain in the steel when P is applied Table 1- Column Details OD E fs, allow 18 in. 29000 ksi 27 ksi ID Ec fc, allow 17.5 in. 3600 ksi 3 ksiQ # 2. Design an interior span slab of a concrete floor system with the following description: Span = 10 m Imposed dead load= 766 N/m² Live load= 4788 N/m? fc'= 27.58 MPa fy = 413.64 MPa (CLO2-C5/PLO3) (15)
- Please show clear and detailed solution thank you! Problem: A column shown is 15-feet long and consists of W14x90 with two plates welded to form a box section. Given: The thickness of the plate = 0.5 in. 1.) Compute the effective slenderness ratio along the x-axis or strong axis. 2.) Compute the effective slenderness ratio along the y-axis or weak axis. 3.) Compute the Euler Load . 4.) Compute the design strength... Determine whether the D = 560 kips L = 68 kips compression member shown is adequate to support the given service loads. Take note Pu = 1.4D. 20' W12 × 79 K= 0.80, r= 3.05 in E = 29000 ksi, Fy = 50 ksi %3D A992 steel %3D Input Yes or No for your final answer. Note: Ag = 23.2 in^2 Blank 1 Blank 1 Add your answerure B 2m2 m C -2 m D 4 m 500 N 700 N 2 of 2 Part B Identify the zero-force members in the truss shown in (Figure 2). Check all that apply. 000 CD DE CG CF FG BC BG DF AG EF AB Submit Provide Feedback Request Answer
- O 88 130% v - + I Annotate T| Edit Trial expired Unlock Full Version ENGR 263 + A A A T O 4.10 Member AB is the beam under consideration. As shown in the illustration of the loading condition, member AB is an overhanging beam that supports a uniformly distributed roof load of 500 lb/ft. It also carries concentrated loads from a rooftop HVAC unit (4000 lb), an interior hanging display support (2000 lb), and a marquee sign (3000 lb). Marquee overnang Displau SLIPPort II Raof Kiots Ol I W = 500 Ib/Ft A B 4000 b 2000 000 I Steel beam !! I1 3 FE 5 FE - Ft RoOFtop HVAC unit 10 FE 4 Ft Marquee sign< R R2 Steel beam (negligible weight) Free-body diagram Dispiay Support Loading conditionDetermine the ASD and LRFD compressive strength of the column.E CH2- Resultant paf - Adobe Acrobat Pro Estended Fle Edit View Document Comments Forms Tools Advanced Windew Help 2/87 If the resultant of the two forces and couple M passes through point O, determine M. 150 mm 60° mm 30 M, = M-400x 0.15cos30-320x0.3 0 M = 148 Nm CCW 320 N 160 400 N mm Example : Replace the three forces acting on the bent beam by a single equivalent force R. Specify the distance x from the point O in which the line of action of R passes. 200 N 160 N ahid hamoodi •..