2 2. A survey was conducted for a certain trait (the ability to roll tongue or inability to roll the tongue) in a population. The result shows that 215 of the respondents can roll their tongue and 85 cannot roll their tongue. The picture below shows a person rolling his tongue. Rolling the tongue into a tube shape is often described as a dominant trait. If the dominant allele is represented by R (can roll tongue) and r represents the recessive allele, calculate the phenotypic frequencies, allele frequencies, the expected numbers of the three genotypic classes and the expected numbers of the two phenotypic classes (assuming random mating). Using chi-square test, determine whether or not this population is in Hardy-Weinberg equilibrium. REMEMBER: Genotype Phenotype Can roll tongue Cannot roll tongue HWE term p2 and 2pq q2 RR and Rr rr

2 2. A survey was conducted for a certain trait (the ability to roll tongue or inability to roll the tongue) in a population. The result shows that 215 of the respondents can roll their tongue and 85 cannot roll their tongue. The picture below shows a person rolling his tongue. Rolling the tongue into a tube shape is often described as a dominant trait. If the dominant allele is represented by R (can roll tongue) and r represents the recessive allele, calculate the phenotypic frequencies, allele frequencies, the expected numbers of the three genotypic classes and the expected numbers of the two phenotypic classes (assuming random mating). Using chi-square test, determine whether or not this population is in Hardy-Weinberg equilibrium. REMEMBER: Genotype Phenotype Can roll tongue Cannot roll tongue HWE term p2 and 2pq q2 RR and Rr rr

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter21: Microevolution: Genetic Changes Within Populations

Section: Chapter Questions

Problem 7TYK: A population of mice is at HardyWeinberg equilibrium at a gene locus that controls fur color. The...

See similar textbooks

Similar questions

26. Snow geese (Chen caerulescens) come in two color types, white “snows” and “blues” with dark bodies. A single gene controls coloration, where the dark (“blue”) allele (D) is dominant. A population of 30,012 geese includes 9236 dark individuals. Genetic testing reveals that 7636 of the 9236 dark individuals are heterozygous (Dd). What is the actual frequency of allele D? 0.819 0.181 0.435 0.347
2. A survey was conducted for a certain trait (the ability to roll tongue or inability to roll the tongue) in a population. The result shows that 215 of the respondents can roll their tongue and 85 cannot roll their tongue. The picture below shows a person rolling his tongue. Rolling the tongue into a tube shape is often described as a dominant trait. If the dominant allele is represented by R (can roll tongue) and r represents the recessive allele, calculate the phenotypic frequencies, allele frequencies, the expected numbers of the three genotypic classes and the expected numbers of the two phenotypic classes (assuming random mating). Using chi-square test, determine whether or not this population is in Hardy-Weinberg equilibrium. REMEMBER: Phenotype RR and Rr Can roll tongue Cannot roll tongue Genotype HWE term p2 and 2pq q? rr Again, follow the format below for your answers. Regarding letter "F" on the format, you will show the computations on how you arrive to the chi-square value…
1. The ability to taste the compound PTC is controlled by a dominant allele T, while individuals homozygous for the recessive allele (t) cannot taste PTC. In a population consisting of 500 individuals, 347 are tasters and 153 are non-PTC tasters. Calculate the frequency of the T and t alleles in this population, and frequency of the genotypes.(Please train yourself to use the Hardy-Weinberg equation.)To present your answers, follow the format in the picture below.
25., Snow geese (Chen caerulescens) come in two color types, white “snows” and “blues” with dark bodies. A single gene controls coloration, where the dark (“blue”) allele (D) is dominant. A population of 30,012 geese includes 9236 dark individuals. Genetic testing reveals that 7636 of the 9236 dark individuals are heterozygous (Dd). How many individuals are dd? 7636 13140 1600 20776
6. In a population of mice, coat color is controlled by a single additive locus. BB mice are black, bb mice are white, and Bb mice are grey. The population is currently in HWE, with 1% of the mice having the white phenotype. Grey mice have twice as many offspring as black or white mice. What will be the frequency of the b allele in the next generation? The answer is supposed to be 0.16, can you explain how to get to this?
p + q = 1 p2 + 2pq + q2 = 1 p is the frequency of the dominant allele q is the frequency of the recessive allele p2 is the frequency of homozygous dominant genotype q2 is the frequency of homozygous recessive genotype 2pq is the frequency of heterozygous genotype Within a population of roses, the color red (R) is dominant over the color white (r). 40% of all the roses are white.a)The percentage of roses in the population that are heterozygous b) The frequency of homozygous dominant individuals =
1.)The frequency of the R allele for round seeds in a certain population of 500 peas wasfound to be 0.45. How many of them were wrinkled? How many of them had the rr genotype? How many of them were round? 2.)In humans, a dominant allele controls the formation of a cleft chin, a Y-shaped fissurein the chin caused by an atypical bone formation in the mandible (this phenotypeis also known as a chin dimple). A survey of 1200 college students found that108 of them did not have a cleft chin. What was the frequency of heterozygotes inthat student population?
14. In class we explored how genotype frequencies can change between generations. In our experiment, we started with a population in which every individual was heterozygous for a few traits of interest. The data for the 11 offspring of these heterozygotes are below. Make sure you show at least some work for partial credit. Frecueles Eje coloN Freckles Genotype FF Eye Shape Genotype EE Eye Color Genotype RR (P 3 (P 3 Ff 5 Ee .0.3 1-0.3 3 RB 7 ff 1 ее Phenotypes Freckles No freckles Phenotypes Phenotypes Red |-0.3 FF, Ff Circle EE, Ee RR Ro.HFF) ff Star ее Purple Blue RB or BR 20.42 BB a) What were the initial allele frequencies for freckles in the starting population? FF=0.42 b) What percentage of the starting population had purple eyes? c) What are the allele frequencies for freckles after one generation? (FF)P= 0.7 (FN 2pf=0.42 (fF) = 03 d) What percentage of the population had purple eyes after one generation? e) Are the genotype frequencies for eye shape what you would expect based…
5. The human ABO blood groups are A, B, AB and O. They are determined by a single gene with multiple alleles. Iª and 1³ alleles are codominant, but both these alleles are dominant to the lº allele. In a maternity ward, the identities of four babies became accidentally mixed up. The ABO blood groups of the babies were discovered to be O, A, B and AB. The ABO blood groups of the four sets of parents were determined and are shown in the table below. Complete the table to match each baby to its parents by indicating: the parental genotypes, using the symbols IA, IB and 10; the blood group of the baby which belongs to each set of parents. baby blood group . parental blood groups O and O AB and O A and O AB and A parental genotypes
4.Eyelash length is an inherited trait. In the human population, there is an eyelash length gene. There are two possible variants of this gene—an allele for long eyelashes (> 1cm) and an allele for short eyelashes (1 cm or less). The allele for long eyelashes is dominant (L) and the allele for short eyelashes is recessive (l). An individual who is heterozygous for eyelash length would have which of the following genotypes? A.Short eyelashes B.Ll C.LL D.Long eyelashes
19.Eyelash length is an inherited trait. In the human population, there is an eyelash length gene. There are two possible variants of this gene—an allele for long eyelashes (> 1cm) and an allele for short eyelashes (1 cm or less). The allele for long eyelashes is dominant (L) and the allele for short eyelashes is recessive (l). An individual who is heterozygous for eyelash length would produce which of the following gametes? A. None of the gametes would have the eyelash gene; gametes do not have eyelashes. B. The proportion of gametes receiving each allele would be random; the process of meiosis is very disorganized and chromosomes are not separated in an ordered fashion. C. All gametes would have the l allele. D. Half of the gametes would have the L allele and half of the gametes would have the l allele.
population is black in colour but about 1/4 of them are white. gene (B) that produces an enzyme that converts a pigment molecule to produce the Black colour. There are 2 alleles of this gene - the dominant B and the recessive b. DNA analysis shows that black individuals have either a BB or Bb genotype and that white individuals have a bb phenotype. However, you have discovered that a small percentage of White individuals have either a BB or Bb genotype. Explain two reasons that could explain this apparent anomaly. They have a BB or Bb genotype but a white phenotype.