17:55 Mon, 29 Apr M Problem Sheet 4 Electroanalysis_918840047 - Saved Insert Draw Layout Review View File Home I U X, More Formatting E E⭑ A 3. The calibration data for the determination of lead levels in fruit juices by a differential pulse polarography method is shown below. [Pb]/ugL-1 Current/μA 0 0.000 0.118 5 10 20 30 40 50 0.240 0.507 0.713 0.981 1.183 When these data were plotted using linear regression a correlation coefficient, R2, of 0.9988 and a line of best fit were obtained; y= 0.0239x+0.005 Use this information to determine the lead levels in the unknown sample, which had been diluted by a factor of 25, from the following replicate measurements; 0.475, 0.481, 0.486, 0.479 and 0.484 μA. 65% KC

Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter17: Applications Of Infrared Spectrometry
Section: Chapter Questions
Problem 17.9QAP
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17:55 Mon, 29 Apr M
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3. The calibration data for the determination of lead levels in fruit juices by a differential pulse
polarography method is shown below.
[Pb]/ugL-1
Current/μA
0
0.000 0.118
5
10
20
30
40
50
0.240 0.507 0.713 0.981
1.183
When these data were plotted using linear regression a correlation coefficient, R2, of 0.9988
and a line of best fit were obtained;
y= 0.0239x+0.005
Use this information to determine the lead levels in the unknown sample, which had been
diluted by a factor of 25, from the following replicate measurements; 0.475, 0.481, 0.486,
0.479 and 0.484 μA.
65%
KC
Transcribed Image Text:17:55 Mon, 29 Apr M Problem Sheet 4 Electroanalysis_918840047 - Saved Insert Draw Layout Review View File Home I U X, More Formatting E E⭑ A 3. The calibration data for the determination of lead levels in fruit juices by a differential pulse polarography method is shown below. [Pb]/ugL-1 Current/μA 0 0.000 0.118 5 10 20 30 40 50 0.240 0.507 0.713 0.981 1.183 When these data were plotted using linear regression a correlation coefficient, R2, of 0.9988 and a line of best fit were obtained; y= 0.0239x+0.005 Use this information to determine the lead levels in the unknown sample, which had been diluted by a factor of 25, from the following replicate measurements; 0.475, 0.481, 0.486, 0.479 and 0.484 μA. 65% KC
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