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12 (a) (b) Describe how you can obtain the integrated form of the Clapeyron equation as below. State any assumptions you have to make. Afus H (T-T) P₂≈ P₁+ AfusV T₁ The heat of fusion (Afus H) of Hg at its normal melting point (-38.9 °C) is 2.82 cal.g¹. The densities of Hg(s) and Hg(1) at -38.9 °C and 1 atm are 14.193 and 13.690 g cm Estimate the melting point of Hg at 100 atm using the result in (a). respectively. Ans 234.8K or -38.4°C

12 (a) (b) Describe how you can obtain the integrated form of the Clapeyron equation as below. State any assumptions you have to make. Afus H (T-T) P₂≈ P₁+ AfusV T₁ The heat of fusion (Afus H) of Hg at its normal melting point (-38.9 °C) is 2.82 cal.g¹. The densities of Hg(s) and Hg(1) at -38.9 °C and 1 atm are 14.193 and 13.690 g cm Estimate the melting point of Hg at 100 atm using the result in (a). respectively. Ans 234.8K or -38.4°C

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter11: Solutions And Colloids
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Problem 7E: Heat is released when some solutions form; heat is absorbed when other solutions form. Provide a...
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12 (a) (b) Describe how you can obtain the integrated form of the Clapeyron equation as below. State any assumptions you have to make. Afus H (T-T) P₂≈ P₁+ AfusV T₁ The heat of fusion (Afus H) of Hg at its normal melting point (-38.9 °C) is 2.82 cal.g¹. The densities of Hg(s) and Hg(1) at -38.9 °C and 1 atm are 14.193 and 13.690 g cm Estimate the melting point of Hg at 100 atm using the result in (a). respectively. Ans 234.8K or -38.4°C
Transcribed Image Text:12 (a) (b) Describe how you can obtain the integrated form of the Clapeyron equation as below. State any assumptions you have to make. Afus H (T-T) P₂≈ P₁+ AfusV T₁ The heat of fusion (Afus H) of Hg at its normal melting point (-38.9 °C) is 2.82 cal.g¹. The densities of Hg(s) and Hg(1) at -38.9 °C and 1 atm are 14.193 and 13.690 g cm Estimate the melting point of Hg at 100 atm using the result in (a). respectively. Ans 234.8K or -38.4°C
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