1. A rock is thrown upward with a velocity of 20 meters per second. Its height, in meters, t seconds later is given by the function h(t) = 20t - 4.9t² a. Determine the average velocity of the rock over the time interval [1,1.1] b. Determine the average velocity of the rock over the time interval [1,1.01] c. Determine the average velocity of the rock over the time interval [1,1.001] d. Using the results from parts a-c, estimate the instantaneous velocity of the rock at 1 second.

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Chapter3: Polynomial Functions
Section3.5: Mathematical Modeling And Variation
Problem 7ECP: The kinetic energy E of an object varies jointly with the object’s mass m and the square of the...
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1. A rock is thrown upward with a velocity of 20 meters per second. Its height, in meters, t seconds later is
given by the function h(t) = 20t - 4.9t²
a. Determine the average velocity of the rock over the time interval [1,1.1]
b. Determine the average velocity of the rock over the time interval [1,1.01]
C. Determine the average velocity of the rock over the time interval [1,1.001]
d. Using the results from parts a-c, estimate the instantaneous velocity of the rock at 1 second.
2. Use a table of values to estimate the value of the limit. Sketch your table, showing at least six
appropriate inputs and outputs (to five decimal places) that lead to your conclusion.
lim
x→0
√x + 16-4
X
Transcribed Image Text:1. A rock is thrown upward with a velocity of 20 meters per second. Its height, in meters, t seconds later is given by the function h(t) = 20t - 4.9t² a. Determine the average velocity of the rock over the time interval [1,1.1] b. Determine the average velocity of the rock over the time interval [1,1.01] C. Determine the average velocity of the rock over the time interval [1,1.001] d. Using the results from parts a-c, estimate the instantaneous velocity of the rock at 1 second. 2. Use a table of values to estimate the value of the limit. Sketch your table, showing at least six appropriate inputs and outputs (to five decimal places) that lead to your conclusion. lim x→0 √x + 16-4 X
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